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Simora [160]
3 years ago
15

Two equal mass carts approach each other with velocities equal in magnitude but opposite in direction. Friction can be neglected

. If the carts collide completely inelastically, what will be the final velocity of the combined system?
To the left with half the initial velocity
Not enough information!
0
To the right with half the intial velocity
Physics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

0

Explanation:

Since momentum is given by:

\vec{p}=m.\vec{v}

Therefore momentum is a vector quantity in the direction of velocity.

  • Inelastic collision is the type of collision in which the masses combine after collision and start moving in the direction of the greater momentum but here in this case we have the momentum equal and opposite in direction.

<u>This case can be described mathematically as:</u>

m_1.\vec{v_1}=m_2.\vec{v_2}

since the mass and velocity are equal:

m.\vec{v}=m.\vec{v}

net momentum:

p_{net}=0

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Suppose a current flows through a copper wire. Which two things occur?
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a

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What is the mechanical advantage of a 8 m ramp that rises 2 m to a stage?
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Answer:

Mechanical advantage = 4

Explanation:

Given the following data;

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A long jumper can jump a distance of 7.4 m when he takes off at an angle of 45° with respect to the horizontal. Assuming he can
GenaCL600 [577]

Answer:

0.02 m

Explanation:

R₁ = initial distance jumped by jumper = 7.4 m

R₂ = final distance jumped by jumper = ?

θ₁ = initial angle of jump = 45°

θ₂ = final angle of jump = 42.9°

v = speed at which jumper jumps at all time

initial distance jumped is given as

R_{1}=\frac{v^{2}Sin2\theta _{1} }{g}

final distance jumped is given as

R_{2}=\frac{v^{2}Sin2\theta _{2} }{g}

Dividing final distance by initial distance

\frac{R_{2}}{R_{1}}=\frac{Sin2\theta _{1}}{Sin2\theta _{2}}

\frac{R_{2}}{7.4}=\frac{Sin2(42.9)}{Sin2(45))}

R_{2} =7.38

distance lost is given as

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d = 0.02 m

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