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Simora [160]
3 years ago
15

Two equal mass carts approach each other with velocities equal in magnitude but opposite in direction. Friction can be neglected

. If the carts collide completely inelastically, what will be the final velocity of the combined system?
To the left with half the initial velocity
Not enough information!
0
To the right with half the intial velocity
Physics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

0

Explanation:

Since momentum is given by:

\vec{p}=m.\vec{v}

Therefore momentum is a vector quantity in the direction of velocity.

  • Inelastic collision is the type of collision in which the masses combine after collision and start moving in the direction of the greater momentum but here in this case we have the momentum equal and opposite in direction.

<u>This case can be described mathematically as:</u>

m_1.\vec{v_1}=m_2.\vec{v_2}

since the mass and velocity are equal:

m.\vec{v}=m.\vec{v}

net momentum:

p_{net}=0

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The kinetic energy of plane is 10285000 J

Kinetic energy is defined as the energy possed by an object in motion. The mathematical representation of kinetic energy is given below:

<h3>KE = ½mv²</h3>

Where:

KE is the kinetic energy

m is the mass of the object

v is the velocity of the object.

With the above formula, we can obtain kinetic energy of the plane as follow:

Mass (m) = 6800 kg

Velocity (v) = 55.0 m/s

<h3>Kinetic energy (KE) =? </h3>

KE = ½mv²

KE = ½ × 6800 × 55²

KE = 3400 × 3025

<h3>KE = 10285000 J</h3>

Therefore, the kinetic energy of plane is 10285000 J

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