Answer:
<h3>
30.66m</h3>
Explanation:
Using the equation of motion formula 
where;
S is the height to which the ball rises
u is the initial velocity of the ball = 0m/s
a is the acceleration due to gravity = 9.81m/s²
t is the time taken by the ball in air = 5.0s
Note that the time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s
Substituting the given parameters into the formula above to get S:
This means that the ball rises 30.66m before it reaches its peak.
If it isn't enough energy to make the jump from 1 energy level to the next energy level, then it will go no where
Answer:
The elevator's velocity after 6 seconds is 3.189m/s
Explanation:
Using Newton's 2nd law:Fnet = ma
Mg - N = ma
Where m = mass
N = normal force
a = acceleration
g = acceleration due to gravity
Substituting the given values and finding acceleration
(95kg)(9.8m/s^2) - 830N = 95kg x a
a = (931 -830) / 95
a = 101/95
a = 1.063m/s^2
After 3 seconds, the weight 0f the person is equal to the actual weight of the person, thus the elevator will be moving at a constant velocity.
Using kinematic equation:
V = u + at
Where V = final velocity
U = initial velocity = 0
a = acceleration
t = time
V = 0 + 1.063 × 3
V = 3.189m/s
This velocity does not change . The elevator travels the test of the time at the same velocity. Therefore,the velocity at 6 seconds = 3.189m/s
By Newton's second law, the net force exerted on the object makes it undergo an acceleration a such that
(2 kg) a = 5 N
so that it is accelerated a = 2.5 m/s^2.
Since the object starts with velocity 3 m/s, after 7 s its acceleration will make it speed up to
3 m/s + (2.5 m/s^2) (7 s) = 20.5 m/s
