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3 years ago

The pituitary gland releases chemicals known as?

Physics

1 answer:

RoseWind [281]3 years ago

5 0

Answer: Endorphins

Explanation:

The pituitary gland releases chemicals that are called as endorphins. These are the polypeptides which are made by the pituitary gland as well as the central nervous system. These are a kind of hormone which helps in dealing with the situations of stress and reduces the pain.

The pressure effect associated with the hormone endorphins is the part related to the increase in concentration of the dopamine production due to the activity of endorphins.

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To add to the complexity, those precious atoms face the peril of disintegrating into the void. Luckily, by now, they are feeling

miskamm [114]

Answer:

B The most basic atoms were formed due to the force of gravity.

Explanation:

Since the statement says that the atoms could have faced the peril of disintegrating into the void, this means that, they could have been destroyed by movement away into the void.

But, it also says that by now, they are feeling the influence of gravity to bring them safely together. This statement shows that gravity brings them (the atoms) together and thus doesn't allow them disintegrate into the void.

So, a reader can thus infer that the most basic atoms were formed due to the force of gravity since it doesn't allow the atoms disintegrate into the void.

So, B is the answer.

5 0

2 years ago

Light in the air is incident at an angle to the surface of (12.0 A) degrees on a piece of glass with an index of refraction of (

Orlov [11]

The question is incomplete. You dis not provide values for A and B. Here is the complete question

Light in the air is incident at an angle to a surface of (12.0 + A) degrees on a piece of glass with an index of refraction of (1.10 + (B/100)). What is the angle between the surface and the light ray once in the glass? Give your answer in degrees and rounded to three significant figures.

A = 12

B = 18

Answer:

18.5⁰

Explanation:

Angle of incidence i = 12.0 + A

A = 12

= 12.0 + 12

= 14

Refractive index u = 1.10 + B/100

= 1.10 + 18/100

= 1.10 + 0.18

= 1.28

We then find the angle of refraction index u

u = sine i / sin r

u = sine24/sinr

1.28 = sine 24 / sine r

1.28Sine r = sin24

1.28 sine r = 0.4067

Sine r = 0.4067/1.28

r = sine^-1(0.317)

r = 18.481

= 18.5⁰

4 0

2 years ago

The picture is attached.

VLD [36.1K]

Answer:

Explanation:

5 0

3 years ago

Read 2 more answers

In the equation Ca(s) + 2H2O(l) -->Ca(OH)2(aq) + H2(g) list each element used as a reactant, and tell how many atoms of each

Mekhanik [1.2K]

The reactants are Calcium, Hydrogen and Oxygen.

We need 1 atom of Calcium, 4 atoms of Hydrogen and 2 atoms of Oxygen.

Hope this helps.

r3t40

3 0

3 years ago

A sailboat moves north for a distance of 15.00 km when blown by a wind from the exact southeast with a force of 3.00 x 10^-4 N.

Zolol [24]

These are actually 4 different exercises:

ex 1) The sailboat moves north, while the wind moves from southeast. This means the angle between the direction of the boat and the wind is $45^{\circ}$ .

Calling F the force of the wind, and $d=15~km=15000~m$ the distance covered by the boat, the work done by the wind is:
$W=Fdcos{\theta}=3\cdot10^{-4}~N \cdot 15000~m\cdot cos 45^{\circ}=3.18~J$

The total time of the motion is $t=1~h=3600~s$ and therefore the power of the wind is
$P= \frac{W}{t} = \frac{3.18~J}{3600~s}=8.8\cdot10^{-4}~W$

ex 2) First of all, let's calculate the length of the ramp. Given the two sizes 2.00 m and 6.00 m, we have
$d= \sqrt{(2~m)^2+(6~m)^2}= 6.32~m$

The mechanical advantage (MA) of the ramp is the ratio between the output load (W) and the input force (F). The output load is the weight of the load, mg, therefore:
$MA= \frac{W}{F}= \frac{mg}{F}= \frac{195~Kg\cdot 9.81~m/s^2}{750~N}=2.55$

Finally, the efficiency $\epsilon$ of the ramp is the ratio between the output energy and the work done. The output energy is simply the potential energy (Ep) of the load, which is mgh, where h is the height of the ramp. The work done W is the product between the input force, F, and the displacement of the load, which is the length of the ramp: Fd. Therefore:
$\epsilon = \frac{E_p}{W}= \frac{mgh}{Fd}= \frac{195~Kg \cdot 9.81~m/s^2\cdot 2~m}{750~N\cdot6.32~m}=0.81$

ex 3) the graph is missing

ex 4) We know that the power is the ratio between the work done W and the time t:
$P= \frac{W}{t}$
But we can rewrite the work as
$W=Fdcos\theta$
where F is the force applied, d the displacement of rock and $\theta=60^{\circ]$ is the angle between the direction of the force and the displacement (3 m).
Therefore we can rewrite the power as
$P= \frac{W}{t} = \frac{F d cos\theta}{t}=F v cos\theta$
where $v=d/t=5~m/s$ is the velocity, Using the data of the exercise, we can then find the force, F:
$F= \frac{P}{v cos\theta} = \frac{250~W}{5~m/s \cdot cos 60^{\circ}}=100~N$

and now we can also calculate the work, which is
$W=Fdcos 60^{\circ}=100~N\cdot 3~m \cos60^{\circ}=150~J$

3 0

3 years ago