Answer:
last choice
Explanation:
oxidation and reduction can be defined in terms of adding or removing oxygen to a compound
oxidation is gaining oxygen
reduction is to loss oxygen
Answer:
In advance
middle
lower
Explanation:
These are the safety precautions needed when carrying out duties in the fume hood.
When planning and preparing to work in a fume hood (a locally designed area to reduce exposure to hazardous fumes). It is advisable to make all equipment readily available at your disposal <u>in advance</u> to reduce and minimize the raising and lowering of the hood sash at intervals.
It is also pertinent to understand that working in the<u> middle </u>of the work surface helps to promote the movement of air and keeps the area neat and tidy.
However, if any case where there is a need to get a new tool or equipment during the process of working in a fume hood, it is advisable to <u>lower </u>the sash at that point in time.
Answer:
The effective nuclear charge for a valence electron in oxygen atom:
Explanation:
Effective nuclear charge is the net nuclear charge experienced by the electron in a given atom. It is always less than the actual charge of the nucleus [Z], due to shielding by electrons in the inner shells.
<em>It is equal to the difference between the actual nuclear charge or the atomic number (Z) and the shielding constant (s). </em>
<u>For an oxygen atom</u>-
Electron configuration: (1s²) (2s² 2p⁴)
<em>The atomic number (actual nuclear charge): </em>Z = 8
The shielding constant (s) for a valence electron can be calculated by using the Slater's rules:
⇒ s = 5 × 0.35 + 2 × 0.85 = 1.75 + 1.7 = 3.45
<u><em>Therefore, the effective nuclear charge for a valence electron in oxygen atom is:</em></u>
<u>Therefore, the effective nuclear charge for a valence electron in oxygen atom:</u>
Explanation:
The given data is as follows.
n = 1 mol,
Q = 1500 J, R = 8.314 J/mol k
(a)
And, according to the first law of thermodynamics
And, in an isothermal process the change in internal energy of the gas is zero.
Hence, 0 = Q - W
or, W = Q
Expression for work done in an isothermal process is as follows.
W =
As W = Q, Hence expression for Q will also be given as follows.
Q =
Now,
[/tex]\Delta S = nR ln \frac{V_{f}}{V_{i}}[/tex]
=
= nR ln 2
=
= 5.76 J/K
Therefore, change in entropy is 5.76 J/K.
(b) As, Q =
=
= nRT ln 2
T =
=
= 260.4 K
Therefore, temperature of the gas is 260.4 K.