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DanielleElmas [232]
3 years ago
12

Why are large numbers of animals found in areas where upwelling occurs

Chemistry
1 answer:
Ivan3 years ago
7 0
Answer: this is because nutrients are increased by the movement of water.

Hope this helps! ^^
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Which describes how transuranium elements are made in a lab?
Vinil7 [7]

transmutation. the conversion of an atom of one element to an atom of another element

8 0
3 years ago
Read 2 more answers
What are the 6 steps to solving a mass-mass problem
aev [14]

Answer:

  • Write a balanced equation for the reaction.
  • Write the given mass on a factor-label form.
  • Convert mass of reactant to moles of reactant.
  • Convert moles of reactant to moles of product.
  • Convert moles of product to grams of product.
  • Pick up the calculator and do the math.

Explanation:

Can I get Brainiest.

4 0
4 years ago
Worth 40 Points❤ 10th grade chemistry ‍
brilliants [131]

Answer:

  1. F
  2. E
  3. G
  4. A
  5. C
  6. B
  7. D

Explanation:

Those are the answers in order, BUT the Goldstein and Rutherford ones are confusing me because Rutherford discovered<em> protons</em> and the <em>nuclear atom</em>. Through my research I also noticed that Goldstein contributed to the discovery of the protons made Rutherford, so I listed him as the one who discovered the proton.

I hope this helps! Have a wonderful night! :D

6 0
3 years ago
Outline the steps needed to determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
kumpel [21]

Answer : The limiting reactant is O_2

Explanation : Given,

Mass of C_3H_8 = 30.0 g

Mass of O_2 = 75.0 g

Molar mass of C_3H_8 = 44 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_3H_8 and O_2.

\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{30.0g}{44g/mole}=0.682moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{75.0g}{32g/mole}=2.34moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

From the balanced reaction we conclude that

As, 5 mole of O_2 react with 1 mole of C_3H_8

So, 2.34 moles of O_2 react with \frac{2.34}{5}\times 1=0.468 moles of C_3H_8

From this we conclude that, C_3H_8 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Therefore, the limiting reactant is O_2

5 0
3 years ago
What happens to the air as it gets farther from the heat source?
Effectus [21]

Answer:

molecules heat and move faster, they are moving apart. So air, like most other substances, expands when heated and contracts when cooled.

Explanation:

Because there is more space between the molecules, the air is less dense than the surrounding matter and the hot air floats upward.

6 0
3 years ago
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