To find the ratio of the the combination for the ion, write the charge of the cation as the subscript for the anion, and the charge of the anion as the subscript of the cation. This will make the charges effectively cancel and you will be left with a neutral ionic compound. Remember, that an ionic compound is made up of a metal and a nonmetal.
For Ca2+ and Cl-, you will get the neutral compound to be CaCl₂.
1. D
2. DR
3. SR
4. DR
5. C
6. SR
7. S
8. D
10. C
If I remember correctly, you would have to heat the reaction beaker over a burner..
I apologize if I'm wrong
It’s A
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