All categories

3 years ago

Which type of matter is likely to absorb the most sound waves? A. Metal door B. Loudspeaker C. Hot air O D. Foam wall

Physics

2 answers:

sashaice [31]3 years ago

8 0

Answer:

its either A or D

Explanation:

They use foam walls in like asylums but in the movies all the bad guys say "They can't hear you the metal is too thick" so its either one of those, hope it helped

alina1380 [7]3 years ago

6 0

Answer:

I think D...

Explanation:

You might be interested in

How does mass differ from weight? List 2 differences.

Alinara [238K]

weight is vector vary from place to place

5 0

2 years ago

Read 2 more answers

3. Which one of these has the most inertia?

Arte-miy333 [17]

b. A Boeing 747 airplane

Explanation:

The Boeing 747 airplane will have the most inertia of all. Inertia is the tendency of an object to remain at rest or uniform motion.

Newton's first law of motion is also regarded as the law of inertia.
It states that "an object will remain at rest or uniform motion motion unless acted upon by an external force".
A body that has a large mass will be more resistant to any external force that acts on it.
The Boeing 747 has the most mass of all and will have the most inertia.

Learn more:

Inertia brainly.com/question/691705

#learnwithBrainly

3 0

3 years ago

The 1.53-kg uniform slender bar rotates freely about a horizontal axis through O. The system is released from rest when it is in

OlgaM077 [116]

Answer:

The spring constant = 104.82 N/m

The angular velocity of the bar when θ = 32° is 1.70 rad/s

Explanation:

From the diagram attached below; we use the conservation of energy to determine the spring constant by using to formula:

$T_1+V_1=T_2+V_2$

$0+0 = \frac{1}{2} k \delta^2 - \frac{mg (a+b) sin \ \theta }{2} \\ \\ k \delta^2 = mg (a+b) sin \ \theta \\ \\ k = \frac{mg(a+b) sin \ \theta }{\delta^2}$

Also;

$\delta = \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2}$

Thus;

$k = \frac{mg(a+b) sin \ \theta }{( \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2})^2}$

where;

$\delta$ = deflection in the spring

k = spring constant

b = remaining length in the rod

m = mass of the slender bar

g = acceleration due to gravity

$k = \frac{(1.53*9.8)(0.6+0.2) sin \ 64 }{( \sqrt{0.6^2 +0.6^2 +2*0.6*0.6 sin \ 64} - \sqrt{0.6^2 +0.6^2})^2}$

$k = 104.82\ \ N/m$

Thus; the spring constant = 104.82 N/m

The angular velocity can be calculated by also using the conservation of energy;

$T_1+V_1 = T_3 +V_3 \\ \\ 0+0 = \frac{1}{2}I_o \omega_3^2+\frac{1}{2}k \delta^2 - \frac{mg(a+b)sin \theta }{2} \\ \\ \frac{1}{2} \frac{m(a+b)^2}{3} \omega_3^2 + \frac{1}{2} k \delta^2 - \frac{mg(a+b)sin \ \theta }{2} =0$