Okay, haven't done physics in years, let's see if I remember this.
So Coulomb's Law states that

so if we double the charge on

and double the distance to

we plug these into the equation to find
<span>

</span>
So we see the new force is exactly 1/2 of the old force so your answer should be

if I can remember my physics correctly.
1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

Rearranging the equation, we can write

In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is

2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:

Two, four, eight and sixteen cells are produced from first, second, third and fourth cell division respectively.
<h3>How many cells are produced? </h3>
When the body cell passes through cell division process, it divides into two daughter cells. In the second cell division, two cells divides into four cells. In the third cell division, the four cells divides into eight cells. In the fourth cell division, the eight cells divides and sixteen cells are produced.
So we can conclude that two, four, eight and sixteen cells are produced from first, second, third and fourth cell division respectively.
Learn more about cell division here: brainly.com/question/796780
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I think it’s A not 100% sure
Answer: 91.94 kg
Explanation: Supoose Al's mass is m. The combined mass is 168kg, so Jo's mass is 168 - m.
The Law of Conservation of Momentum states that when two objects collide, the total momentum of both objects before the collision is the same as the total momentum of both objects after the collision.
At the beginning, Al and Jo are united without movement, so their initial momentum is zero.
After the release of their hands, Al goes in one direction and Jo moves to the opposite direction. Suppose the direction Al is moving is positive. Conservation of momentum will be

where
index i referes to initial momentum
index f to final momentum
index 1 refers to Al
index 2 to Jo
Calculating:
![m(0.91)-[(168-m)(1.1)]=0](https://tex.z-dn.net/?f=m%280.91%29-%5B%28168-m%29%281.1%29%5D%3D0)


m = 91.94
Al has a mass of 91.94 kg.