Imagine a string of holiday lights, with many bulbs connected to each other by wires. One bulb burns out, causing the bulbs next
1 answer:
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Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
Answer:
Explanation:
d = Diameter of column = 0.5 inch
= Area of concrete =
The strain in the system is conserved
Now
Stress is given by
The stress in the steel is
The stress in the steel is
Answer:
Potential energy, E = 25 mgh
Explanation:
Given that,
Mass of the object, m = 5 m
It is lifted to a height of, h = 5 h
It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :
E = 25 mgh
So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.