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3 years ago

Find molarity of 29.1 g LiClO4 · 3 H2O in 235 mL of solution

Chemistry

1 answer:

juin [17]3 years ago

3 0

To find molarity

We need no.of moles and solution in liter

Given data is in grams and ml

We have to convert it in required units

For no.of moles use formula

No.of mole=mass in gram / molar mass

Mass in gram = 29.1g

Molar mass = 160.4374g/mol calculated by adding the atomic wight of all atoms in LiClO4.3H2O

Atomic weight

Li= 6.941

Cl= 35.453

O= 15.9994

H= 1.00794

Now put it in mol equation

No.of mole = 29.1/160.4374

= 0.181mol of solute

Now convert solution in L from ml

235ml = 235/1000 = 0.235L

Now put these values in molarity formula

Molarity= 0.181/0.235

= 0.77M solution

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Kamila [148]

Answer:

(D) (CH3CH2)2NH

Explanation:

In order to decide which base is strongest we need to calculate its PKb

PKb = -log [Kb]

A large Kb value and small PKb value gives the strongest base

Compound Kb PKb

(A) C6H5NH2 - 4 x 10^-10 9.349

(B) NH3 1.76x 10^-5 4.754

(D) (CH3CH2)2NH 8.6x 10^-4 3.066

(E) C5H5N 1.7x10^-9 8.77

Clearly (CH3CH2)2NH is the strongest base.

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2 years ago

What is the vapor pressure of the solution if 35.0 g of water is dissolved in 100.0 g of ethyl alcohol at 25 ∘C? The vapor press

masya89 [10]

Answer: The vapor pressure of the solution is 43.55 mmHg

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For water:

Given mass of water = 35.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{35.0g}{18g/mol}=1.944mol$

For ethyl alcohol:

Given mass of ethyl alcohol = 100.0 g

Molar mass of ethyl alcohol = 46 g/mol

Putting values in equation 1, we get:

$\text{Moles of ethyl alcohol}=\frac{100.0g}{46g/mol}=2.174mol$

Total moles of solution = [1.944 = 2.174] moles = 4.118 moles

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For water:

$\chi_{\text{water}}=\frac{n_{\text{water}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}$

$\chi_{water}=\frac{1.944}{4.118}=0.472$

For ethyl alcohol:

$\chi_{\text{ethyl alcohol}}=\frac{n_{\text{ethyl alcohol}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}$

$\chi_{\text{ethyl alcohol}}=\frac{2.174}{4.118}=0.528$

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the vapor pressure of the solution, we use the law given by Dalton, which is:

$P_T=\sum_{i=1}^n (p_i\times \chi_i)$

Or,

$P_T=[(p_{\text{water}}\times \chi_{\text{water}})+(p_{\text{ethyl alcohol}}\times \chi_{\text{ethyl alcohol}}$

We are given:

Vapor pressure of water = 23.8 mmHg

Vapor pressure of ethyl alcohol = 61.2 mmHg

Putting values in above equation, we get:

$p_T=[(23.8\times 0.472)+(61.2\times 0.528)]\\\\p_T=43.55mmHg$

Hence, the vapor pressure of the solution is 43.55 mmHg

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3 years ago

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