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3 years ago

A negative number raised to an odd number is

Mathematics

2 answers:

deff fn [24]3 years ago

4 0

Yes that is totally correct

pashok25 [27]3 years ago

3 0

$\bf \stackrel{\textit{negative raised to an odd power}~\hfill \textit{is still a negative number}}{(-4)^3\implies (-4)(-4)(-4)\implies (16)(-4)\implies -64}$

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2.4 puzzle time how can you share five apples with seven friends

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6 0

3 years ago

Higher Order Thinking.

defon

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3 years ago

Graph h(t)=-2(t+5)^2+3, find h(-8)

NARA [144]

Answer:

h(-8)=-15

Step-by-step explanation:

Substitute t=-8

h(-8) =-2(-8+5)^2+3

=-2(-3)^2+3

=-2(9)+3

=-18+3

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3 years ago

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3 years ago

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what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?

seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

This is a fraction so we have to worry about division by zero.

The only time we will be dividing by 0 is when x+4 is 0.

Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

If is is a vertical asymptote, x=-4 will make the top NOT zero.

Let's see what -4 for x in x^2+6x+8 gives us:

(-4)^2+6(-4)+8

16+-24+8

-8+8

Top and bottom are 0 when x=-4.

Let's see what happens after simplication.

We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

So what 2 numbers together multiply to be 8 and add up to be 6.

I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

$\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2$

We we able to cancel out that factor that was giving us x=-4 is a zero.

Therefore there is a hole at x=-4.

7 0

3 years ago

A negative number raised to an odd number is​

A negative number raised to an odd number is