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prisoha [69]
3 years ago
8

A negative number raised to an odd number is​

Mathematics
2 answers:
deff fn [24]3 years ago
4 0
Yes that is totally correct
pashok25 [27]3 years ago
3 0

\bf \stackrel{\textit{negative raised to an odd power}~\hfill \textit{is still a negative number}}{(-4)^3\implies (-4)(-4)(-4)\implies (16)(-4)\implies -64}

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What is the slope of the line shown?<br><br> -7/9<br> 9/7<br> 7/9<br> -9/7
SpyIntel [72]

To find slope, we must find the change in y values divided by the change in x values, also called the rise/run. This is modeled below:

Slope = m = (y1 - y2)/(x1-x2) = (6-(-3))/(1 - (-6)) = (6+3)/(1+6) = 9/7

We can check that this answer is correct by consulting the graph. The graph shows a positive correlation (means that the slope should be positive), and if you count the graph unit squares, you get that the graph moves up 9 squares and over 7 squares between the two points shown, letting us know we got the right answer.

Hope this helps!

7 0
3 years ago
S is the midpoint of RT. R has the coordinates (-6, -1), and S has coordinates (-1, 1). Find the coordinates of T.
bekas [8.4K]
If the distance from R to S is only half then the other half is S to T. The distance between R and S is (5,2). that should give you the answer
7 0
3 years ago
Read 2 more answers
Find the probability of having 2,3, or 4 successes in five trials of a binomial experiment in which the probability of success i
Georgia [21]

Answer:

65.3%

Step-by-step explanation:

Binomial distribution PMF below (along with a description)

the probabilty of getting 2, 3, or 4 successes in 5 trials is just

p(2)+p(3)+p(4)

p(2)= 5C2*.4²*(1-.4)³ = .3456

p(3)= 5C3*.4³*(1-.4)²= .2304

p(4)= 5C4*.4⁴*(1-.4)=.0768

.3456+.2304+.0768= .6528

6 0
2 years ago
Jessica is walking home from a friend's house. After two minutes she is 1.8 miles from home. Twelve minutes after leaving, she i
yKpoI14uk [10]
I believe Jessica’s rate in miles per hour is 0.9.
4 0
3 years ago
It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi
Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 35000}{7000}

X - 35000 = -1.88*7000

X = 21840

The designed life should be of 21,840 vehicle miles.

3 0
2 years ago
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