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3 years ago

A sound wave will rebound when it encounters what?

Physics

2 answers:

Over [174]3 years ago

8 0

The sound wave will rebound when it is a barrier, hope this helps

goblinko [34]3 years ago

8 0

Answer: A barrier

Explanation: A sound wave requires medium to travel. It travels in air. Frequency is the number of cycles per second of a wave. A light is an electromagnetic wave which can travel through vacuum as well as medium. A sound rebounds when it encounters a barrier i.e. when it does not carry enough energy to travel through it.

Hence, the correct answer is a barrier.

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The two types of vitamins are fat and water soluble?

lianna [129]

Its true hopefully this helps you.

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3 years ago

Why did Kenyatta want to distance himself from the Mau Mau? Check all that apply.

Savatey [412]

Answer:

B and C!

Explanation:

I just did it on edge. I hope this helps!

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3 years ago

Now, consider the resultant electric field e⃗ net at p. with reference to the coordinate system shown in the previous part, whic

Rzqust [24]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices:
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only the y component
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The answer is neither the x nor the y component

5 0

3 years ago

A 5kg mass is pushed with a force of 10N for a distance of 2.5 meters. The work done is

Aliun [14]

W = 25 J

Explanation:

Work done on an object is defined as

$W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}$

7 0

2 years ago

A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 24 m/

PilotLPTM [1.2K]

Answer:

a) Vf = 27.13 m/s

b) It would have been the same

Explanation:

On the y-axis:

$Y=-Vo*sin\theta*t-1/2*g*t^2$

$-8=-24*sin(21)*t-1/2*10*t^2$

Solving for t:

t1 = 0.67s t2= -2.4s

Discarding the negative value and using the positive one to calculate the velocity:

$Vf_y = -Vo*sin\theta-g*t$

$Vf_y = -15.3m/s$

So, the module of the velocity will be:

$Vf=\sqrt{(-15.3)^2+(24*cos(21))^2}$

$Vf=27.13m/s$

If you throw it above horizontal, it would go up first, and when it reached the initial height, the velocity would be the same at the throwing instant. And starting then, the movement will be the same.

3 0

3 years ago