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zavuch27 [327]
3 years ago
14

To measure specific heat, the student flows air with a velocity of 20 m/s and a temperature of 25C perpendicular to the length

of the tube, as illustrated below. In this time she heats the tube electrically, passing a current of 50 mA through the tube wall. The initial temperature of the tube is 25 C. After 10 min of heating, a thermocouple buried inside the tube wall measures a temperature of 31.2 C. The tube core is sealed and the heat lost from the internal surface of the tube is negligible during measurements. Furthermore, the tube is suspended on two thermally insulating supports. What is the specific heat of the tube?

Physics
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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Because there is no record of all things. As we have partially unknow information, it can never be held as a fact.
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Sound that reaches the ears after bouncing off a wall or a floor is called _____.
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Answer:

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n outer space, a constant net force with a magnitude of 140 N is exerted on a 32.5 kg probe initially at rest. A) What accelerat
musickatia [10]

Answer:

a) 4.31 m/s²

b) 215.5 m

Explanation:

a) According to Newton's first law of motion

The net force applied to particular mass produced acceleration, a, according to

F = ma

F = 140 N

m = 32.5 kg

a = ?

140 = 32.5 × a

a = 140/32.5 = 4.31 m/s²

b) Using the equations of motion, we can obtain the distance travelled by the object in t = 10 s

u = initial velocity of the probe = 0 m/s (since it was initially at rest)

a = 4.31 m/s²

t = 10 s

s = distance travelled = ?

s = ut + at²/2

s = 0 + (4.31×10²)/2 = 215.5 m

7 0
3 years ago
What is a good example for newton's 1st law​
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3 years ago
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The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 3.6 N and the angl
Nuetrik [128]
<h3>Answer</h3>

6.6 N pointing to the right

<h3>Explanation</h3>

Given that,

two forces acting of magnitude 3.6N

angle between them = 48°

To find,

the third force that will cause the object to be in equilibrium

<h3>1)</h3>

Find the vertical and horizontal components of the two forces

vertical force1 = sin(24)(3.6)

vertical force2= -sin(24)(3.6)

<em>(negative sign since it is acting on opposite direction)</em>

vertical force3 = sin(24)(3.6) - sin(24)(3.6)

                        = 0

<h3>2)</h3>

horizontal force1 = cos(24)(3.6)

horizontal force2= cos(24)(3.6)

horizontal force3 = cos(24)(3.6) + cos(24)(3.6)

                            = 2(cos(24)(3.6))

                            = 6.5775 N

                            ≈ 6.6 N

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4 0
3 years ago
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