We can answer this using one of the equations of linear
motion:
v = d / t
where:
v = velocity
d = distance
t = time
<span>In the problem, we are asked to find for the time in
which Driver B will catch up to Driver A. Therefore, find the time when dA = dB. Rearranging the
equation and equation dA and dB will result in:</span>
<span>vA * tA = vB * tB
---> 1</span>
It was given that:
vA = 68 mph
tA = tB + 3 (since person A was travelling 3 hours
earlier)
vB = 85 mph
tB = unknown
Substituting into equation 1:
68 * (tB + 3) = 85 * tB
68 tB + 204 = 85 tB
tB = 12 hrs
Therefore driver B would catch up to driver A after 12
hrs.
<span> </span>
From my understanding, the two are opposite. Let me give you each word and what it scientifically means to me.
repetition
occurs when an activity is repeated by the same person
replication
occurs when an activity is repeated by a different person
I hope this completely answers your question! If you need further explanation, please let me know!
~Brooke❤️
The first thing we have to do for this case is write the kinematic equationsto
vf = a * t + vo
rf = a * (t ^ 2/2) + vo * t + ro
Then, for the bolt we have:
100% of your fall:
97 = g * (t ^ 2/2)
clearing t
t = root (2 * ((97) / (9.8)))
t = 4.449260429
89% of your fall:
0.89*97 = g * (t ^ 2/2)
clearing t
t = root (2 * ((0.89 * 97) / (9.8)))
t = 4.197423894
11% of your fall
t = 4.449260429-4.197423894
t = 0.252
To know the speed when the last 11% of your fall begins, you must first know how long it took you to get there:
86.33 = g * (t ^ 2/2)
Determining t:
t = root (2 * ((86.33) / (9.8))) = <span>
4.19742389 </span>s
Then, your speed will be:
vf = (9.8) * (4.19742389) = 41.135 m / s
Speed just before reaching the ground:
The time will be:
t = 0.252 + <span>
4.197423894</span> = <span>
4.449423894</span> s
The speed is
vf = (9.8) * (4.449423894) =<span>
<span>43.603</span></span> m / s
answer
(a) t = 0.252 s
(b) 41,135 m / s
(c) 43.603 m / s
Answer:
i think the answer is 50 kW.h