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Crank
3 years ago
9

What best describes the location of an atom's electrons?

Chemistry
2 answers:
Pavlova-9 [17]3 years ago
7 0
They would be
Around the Nucleus
bogdanovich [222]3 years ago
5 0
The common way electrons are found in shells or orbitals that surround the nucleus of an atom.I hope it helped
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Which statement is true? Energy cannot be created or destroyed. Energy can be destroyed but not created. Energy can be created b
vaieri [72.5K]
Energy can not be created and cannot be destroyed
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6 0
3 years ago
Read 2 more answers
In a solution with a pH of 4, the [OH-] is:<br>1x 10-10<br>1x 10-4<br>10<br>- 1x 10-8<br>​
e-lub [12.9K]

Answer:

1 x 10^-4

Explanation:

Use the equation pH = -log[OH-}

Rearranging it [OH-] = 10^-pH

Plugging in we get [OH-] = 1 x 10^-4

3 0
3 years ago
Select the correct answer.
Illusion [34]

Answer: the new force will be 1/9 of the original force

Explanation: Please see attachment for explanation

5 0
3 years ago
How many moles are in 3.24 x 1020 particles of lead? (show work plz)
lesya [120]
<h3>Answer:</h3>

0.000538 mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.24 × 10²⁰ particles Pb (lead)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                  \displaystyle 3.24 \cdot 10^{20} \ particles \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ particles \ Pb})
  2. Multiply/Divide:                                                                                               \displaystyle 0.000538 \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

Our final answer is in 3 sig figs, no need to round.

7 0
3 years ago
How many grams of ammonia (NH3) can be produced when 25 g of nitrogen gas reacts with 28 grams of hydrogen gas
Elis [28]

Answer:

34 g of NH₃

Explanation:

7 0
3 years ago
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