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jek_recluse [69]
3 years ago
14

What happens to mechanical energy if the potential energy of an object decreases?

Physics
1 answer:
OleMash [197]3 years ago
6 0

D. Mechanical energy remains unchanged.

Mechanical energy = Potential energy + Kinetic energy

So if potential energy decreases, then kinetic energy must increase so that the system is balanced.

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Draw a model diagram to represent water​
satela [25.4K]

Answer:

hope this will help

please give brainliest if correct

5 0
3 years ago
Ignoring friction, what is the acceleration of a 75.0 kg object which is acted upon by an
natulia [17]

Explanation:

we can use the formula F = ma

hence,

500 = 75a

a = 6.666 m/s² or 6(2/3) m/s²

hope this helps.

3 0
2 years ago
How much force is needed to accelerate a 62 kg skier at 3 m/sec2?
Fittoniya [83]

Answer:

<h2>The answer is 186 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 62 kg

acceleration = 3 m/s²

We have the final answer as

force = 62 × 3

We have the final answer as

<h3>186 N</h3>

Hope this helps you

8 0
3 years ago
A mysterious rocket-propelled object of mass 49.5 kg is initially at rest in the middle of the horizontal, frictionless surface
Romashka-Z-Leto [24]

The distance covered by the rocket in the first 5 seconds is 7.13 m

Explanation:

In order to solve the problem, we have to find the acceleration of the rocket. We can do it by using Newton's second law, which states that the net force on the rocket is equal to the product between its mass (m) and its acceleration (a):

F(t)=ma(t)

Where here we have:

F(t)=16.8t is the time-dependent force

m = 49.5 kg is the mass

Solving for a(t),

a(t)=\frac{F(t)}{m}=\frac{16.8t}{49.5}=0.34t[m/s^2]

This is the time-dependent acceleration of the rocket.

By integrating this expression, we  find the velocity of the rocket at time t:

v(t)=\int a(t)dt=\int (0.34t)dt=\frac{0.34t^2}{2}=0.17t^2

where we didn't add the constant term since the velocity at t = 0 is zero (the rocket starts from rest).

By integrating this expression, we then find an expression for the position of the rocket at time t:

x(t)=\int v(t) dt = \int (0.17t^2)dt=\frac{0.17t^3}{3}=0.057t^3

Therefore, the distance covered by the rocket in the first t = 5.00 s is:

x(5)=0.057(5.0)^3=7.13 m

Learn more aboiut force and acceleration:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

8 0
3 years ago
Three children are riding on the edge of a merry-go-round that is 100 kg, has a 1.60-m radius, and is spinning at 20.0 rpm. The
Kay [80]

Answer:

25.33 rpm

Explanation:

M = 100 kg

m1 = 22 kg

m2 = 28 kg

m3 = 33 kg

r = 1.60 m

f = 20 rpm

Let the new angular speed in rpm is f'.

According to the law of conservation of angular momentum, when no external torque is applied, then the angular momentum of the system remains constant.

Initial angular momentum = final angular momentum

(1/2 x M x r^2 + m1 x r^2 + m2 x r^2 + m3 x r^2) x ω =

                                  (1/2 x M x r^2 + m1 x r^2 + m3 x r^2 ) x ω'

(1/2 M + m1 + m2 + m3) x 2 x π x f = (1/2 M + m1 + m3) x 2 x π x f'

( 1/2 x 100 + 22 + 28 + 33) x 20 = (1/2 x 100 + 22 + 33) x f'

2660 = 105 x f'

f' = 25.33 rpm

8 0
3 years ago
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