Answer: The correct answer is "Instrument A is placed closer to Sam than instrument B".
Explanation:
The sound can be soft or loud. Loudness depends on the amplitude of the sound wave. Higher the amplitude, more will be loudness. Lower the amplitude, lesser will be loudness.
Pitch depends on the frequency.
In the given problem, the instruments A and B generate sound waves of the same amplitude and at the same time.
Loudness depends on the sound energy produced as the energy of the sound is directly proportional to the square of the amplitude. It also depends on the distance between the source and the receiver.
Sam records a louder sound from instrument A than from instrument B. It means that there is mismatch in loudness. It can happen due to the placement of the instrument A closer to Sam than instrument B.
Therefore, the correct option is "Instrument A is placed closer to Sam than instrument B".
Answer:
V = 3.6 m/s
Explanation:
Given:
V₀ = 18 m/s
a = - 3,6 m/s² (The motorcycle is slowing down!)
t = 4 s
____________
V - ?
Motorcycle speed:
V = V₀ + a·t
V = 18 + (-3.6)·4 = 3.6 m/s
Answer: 4.675×10^-6 m
Explanation: this is a question under the pattern gotten from an interference experiment.
The formulae below defines the experiment given
y = Rmλ/d
Where y = distance between the center fringe and any other fringe in the pattern = 8cm = 0.08m
m = position of fringe = 1 ( this is because we have only one central band)
λ = wavelength of light used for experiment = 680nm = 6.8×10^-7m
d = width of slit =?
R = distance between slits and screen = 5.5 cm = 0.055m
By substituting the parameters, we have that
0.08 = 0.055 × 1 × 6.8×10^-7/d
By cross multiplying, we have that
0.08 × d = 0.055 × 1 × 6.8×10^-7
d = 0.055 × 1 × 6.8×10^-7/ 0.08
d = 3.74 × 10^-7/ 0.08
d = 46.75×10^-7
d = 4.675×10^-6 m
Answer:
v = 10 m/s
Explanation:
Given that,
Distance covered by a sprinter, d = 100 m
Time taken by him to reach the finish line, t = 10 s
We need to find his average velocity. We know that velocity is equal to the distance covered divided by time taken. So,
v = d/t
Hence, his average velocity is 10 m/s.
