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3 years ago

15

Soccer fields vary in size. A large soccer field is 115 m long and 85.0 m wide. Assume that 1 m equals 3.281 ft. What are its di

mensions in feet

1 answer:

JulsSmile [24]3 years ago

7 0

Answer:

The dimensions are 377.3 feet by 278.9 feet.

Explanation:

Given that,

Length of a soccer field = 115 m

Width of a soccer field = 85 m

We need to assume that, 1 m equals 3.281 ft

We need to find the dimensions in feet.

As 1 m = 3.281 ft

⇒ 115 m = (115×3.281) feet

= 377.315 feet ≅ 377.3 feet

⇒ 85 m = (85×3.281) feet

= 278.885 feet ≅ 278.9 feet

Hence, the dimensions are 377.3 feet by 278.9 feet.

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A carnot heat engine receives 600 kj of heat from a source of unknown temperature and rejects 175 kj of it to a sink at 20°c. de

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(b) 71%

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In this problem, we have:

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(a) $737^{\circ}C$

The efficiency of an engine can also be rewritten as

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$T_H$ is the temperature of the source

In this problem, the temperature of the sink is

$T_C = 20^{\circ}C + 273=293 K$

So we can re-arrange the equation to find the temperature of the source:

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3 years ago

A coil of 1,000 turns encloses an area of 85 cm^2. It is rotated in 0.090 s from a position where its plane is perpendicular to

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The average emf induced in the coil is $5.6\times10^{-3}\ mV$ .

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Given that,

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Area = 85 cm²

Time = 0.090 s

Its plane is perpendicular to Earth's magnetic field.

Angle = 0°

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Using formula of magnetic flux

$\phi=BA\cos\theta$

Put the value into the formula

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$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{5.1\times10^{-7}}{0.090}$

$\epsilon=0.0000056\ N$

$\epsilon =5.6\times10^{-3}\ mV$

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3 years ago