Answer:
If pressure increases, then volume decreases and vice versa, when temperature is held constant.” When pressure increases, the same number of molecules, or matter, are being forced closer together to occupy a shrinking space, their volume decreasing while their density correspondingly increases.
Explanation:
Answer:
pH = 10.11
Explanation:
Hello there!
In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:
We can therefore set up the corresponding equilibrium expression:
![Kb=\frac{[C_{18}H_{21}NO_4H^+][OH^-]}{[C_{18}H_{21}NO_4]}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BC_%7B18%7DH_%7B21%7DNO_4H%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BC_%7B18%7DH_%7B21%7DNO_4%5D%7D)
Which can be written in terms of the reaction extent, 
:
Thus, by solving for we obtain:
However, since negative solutions are now allowed, we infer the correct is 0.0001285 M; thus, the pOH can be computed:
And finally the pH:
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Answer:
Most of these faults are hidden in the deep ocean, where they offset divergent boundaries in short zigzags resulting from seafloor spreading, the best-known (and most destructive) being those on land at the margins of continental tectonic plates. A transform fault is the only type of strike-slip fault that is classified as a plate boundary.
Explanation:
Answer:
B
Explanation:
I picked b because the hider the flow current
The joules required to heat 2L of water in a pot from 20 c to the boiling point of water is calculated using the following formula
Q= MC delta T
M = mass = density x volume( 2 x 1000= 2000ml)
M = 1g/ml x2000 ml = 2000g
C = specific heat capacity = 4.18 g/c
delta T = change in temperature = 100 c ( boiling point of water) - 20 c = 80 c
Q is therefore = 2000 g x 4.18 j/g c x 80c = 668800j
