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Harman [31]
2 years ago
10

A solution has a hydronium or hydrogen ion concentration of 3.16×10^-8M. What is the ph of the solution?

Chemistry
1 answer:
Luba_88 [7]2 years ago
7 0

Answer:

<h2>7.50</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

pH =  -  log(3.16 \times  {10}^{ - 8} )  \\  = 7.500312...

We have the final answer as

<h3>7.50 </h3>

Hope this helps you

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Materials move across a cell membrane in a process called _______.
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Diffusion

Explanation:

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A solution <span>has a uniform composition and is only able to be separated by chemical means.</span>
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The volume of the earth is approximately 1.08326x10 to the 12th power km to the 3rd power. How many liters is this
mafiozo [28]

Here, we are required to determine the volume of the earth which is 1.08326 × 10¹² km³ in liters.

<em>The volume of the earth is approximately</em>,

, 1.08326 × 10²⁴ liters

By conversion factors;

  • <em>1dm³ = 1liter</em>
  • However; <em>1km = 10000dm = 10⁴ </em><em>dm</em>
  • Therefore, 1km³ = (10⁴)³ dm³.

Consequently, 1km³ = 10¹²dm³ = 10¹²liters.

The conversion factor from 1km³ to liters is therefore, c.f = 10¹²liters/km³

Therefore, the volume of the earth which is approximately, 1.08326 × 10¹² km³ can be expressed in liters as;

<em>1.08326 × 10¹² km³ × 10¹²liters/km³ </em>

The volume of the earth is approximately,

1.08326 × 10²⁴ liters.

Read more:

brainly.com/question/16814684

7 0
2 years ago
5. What is the mass of 9.80 x 1023 formula units of zinc chlorate, Zn(CO3)2?
Zielflug [23.3K]

Answer:

\boxed{\text{378 g}}

Explanation:

We must convert formula units of Zn(ClO₃)₂ to moles and then to grams of Zn(ClO₃)₂.

Step 1. Convert formula units to moles

\text{Moles of Zn(ClO$_{3}$)$_{2}$}\\\\= 9.80 \times10^{23}\text{ formula units Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}{6.022 \times\ 10^{23} \text{ formula units Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$}

Step 2. Convert moles to grams

\text{Mass of Zn(ClO$_{3}$)$_{2}$}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{232.29 g Zn(ClO$_{3}$)$_{2}$}}{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{378 g Zn(ClO$_{3}$)$_{2}$}\\\\\text{The mass of Zn(ClO$_{3}$)$_{2}$ is } \boxed{\textbf{378 g}}

5 0
3 years ago
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