Answer:
Work done, W = 750 joules
Explanation:
It is given that,
Force acting on the object, F = 50 N
It moves to a distance of, d = 15 meters
We need to find the work done on an object. We know that the product of force and distance covered is called the work done. As the force and the displacement are in same direction. So,


W = 750 joules
So, the work done on an object is 750 joules. Hence, this is the required solution.
The object will come to a halt.
Resultant force at start:17-10=7 to the left
When additional force is added to the right,it balances the forces acting in the object.
7N to the right and 7N to the left suggests that the object will come to a halt as it is in equilibrium.
Given:
B =
T
V=
q = 2.5 ×
C
α = 90
To find:
Force = ?
Formula used:
Force on the moving charge is given by,
F = q V B sin α
Where F = force exerted on moving charge
V = velocity of charge
q = charge
α = angle between direction of V and B
Solution:
F = q V B sin α
Where F = force exerted on moving charge
V = velocity of charge
q = charge
α = angle between direction of V and B
F = 
F = 37.5 × 
F = 3.75 Newton
Thus, the force acting on the moving charge is 3.75 Newton.
Answer: False
Explanation:
The potential energy is called organized energy because it is not related to the mass movement of the molecules.
Heat is disorganized energy because it is related to the mass movement of the molecules. Entropy is related to the randomness of the molecules.
If the randomness of the system increases then the entropy will increase. The entropy of the system either remains constant or increases.
The entropy of the system never decreases.
Therefore, the answer will be false.
Answer:
a = 6.7 m/s²
Explanation:
The formula to apply here is :
Mass * acceleration = Tension -weight
m*a = Ft -mg -----where m is mass of block, a is acceleration , Ft is force due to tension.
Given in the question that ;
Mass of block = 3 kg
Ft = 50 N
g= 10
m*a = Ft -mg
3*a = 50-30
3a= 20
a= 20/3
a= 6.7 m/s²