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const2013 [10]
2 years ago
15

What is the total flux φ that now passes through the cylindrical surface? enter a positive number if the net flux leaves the cyl

inder and a negative number if the net flux enters the cylnder. what is ex(p), the value of the x-component of the electric field produced by by the line of charge at point p which is located at (x,y) = (a,0), where a = 9.2 cm?
Physics
1 answer:
trasher [3.6K]2 years ago
8 0

Net flux through the cylindrical surface is given as

\phi = \frac{q}{epsilon_0}

here q = enclosed charge in the surface

so here in order to find the value of q

q = \lambda* L

so now we have

\phi = \frac{\lambda * L}{\epsilon_0}

so this is the total flux

now by Gauss's law we can find the electric field

\int E.dA = \phi

\int E.dA = \frac{\lambda * L}{\epsilon_0}

E* 2\pi rL = \frac{\lambda * L}{epsilon_0}

E = \frac{\lambda}{2\pi \epsilon_0 r}

<em>by above expression we can find the electric field at required position</em>

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What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?
laila [671]

Answer:

Work done, W = 750 joules

Explanation:

It is given that,

Force acting on the object, F = 50 N

It moves to a distance of, d = 15 meters

We need to find the work done on an object. We know that the product of force and distance covered is called the work done. As the force and the displacement are in same direction. So,

W=F\times d

W=50\ N\times 15\ m

W = 750 joules

So, the work done on an object is 750 joules. Hence, this is the required solution.

4 0
3 years ago
An object has a force of 10 newtons from the right and 17 newtons from the left. Once the object starts moving toward the right,
Debora [2.8K]
The object will come to a halt.

Resultant force at start:17-10=7 to the left
When additional force is added to the right,it balances the forces acting in the object.

7N to the right and 7N to the left suggests that the object will come to a halt as it is in equilibrium.
5 0
3 years ago
Read 2 more answers
What is the force exerted on a charge of 2.5 µC moving perpendicular through a magnetic field of 3.0 × 102 T with a velocity of
OverLord2011 [107]

Given:

B = 3 \times 10^{2} T

V=5 \times 10^{3} \frac{m}{s}

q = 2.5 × 10^{-6} C

α = 90

To find:

Force = ?

Formula used:

Force on the moving charge is given by,

F = q V B sin α

Where F = force exerted on moving charge

V = velocity of charge

q = charge

α = angle between direction of V and B

Solution:

F = q V B sin α

Where F = force exerted on moving charge

V = velocity of charge

q = charge

α = angle between direction of V and B

F = 2.5 \times 10^{-6} \times 3 \times 10^{2}  \times 5 \times 10^{3}

F = 37.5 × 10^{-1}

F = 3.75 Newton

Thus, the force acting on the moving charge is 3.75 Newton.

8 0
3 years ago
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In a system, when potential energy decreases, then entropy also decreases.<br><br> True<br> False
Paladinen [302]

Answer: False

Explanation:

The potential energy is called organized energy because it is not related to the mass movement of the molecules.

Heat is disorganized energy because it is related to the mass movement of the molecules. Entropy is related to the randomness of the molecules.

If the randomness of the system increases then the entropy will increase. The entropy of the system either remains constant or increases.

The entropy of the system never decreases.

Therefore, the answer will be false.


8 0
3 years ago
A rope of negligible mass supports a block that weighs 30.0 N. as shown below. The maximum tension the rope can support without
Mars2501 [29]

Answer:

a = 6.7 m/s²

Explanation:

The formula to apply here is :

Mass * acceleration = Tension -weight

m*a = Ft -mg  -----where m is mass of block, a is acceleration , Ft  is force due to tension.

Given in the question that ;

Mass of block = 3 kg

Ft = 50 N

g= 10

m*a = Ft -mg

3*a = 50-30

3a= 20

a= 20/3

a= 6.7 m/s²

8 0
3 years ago
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