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const2013 [10]
3 years ago
15

What is the total flux φ that now passes through the cylindrical surface? enter a positive number if the net flux leaves the cyl

inder and a negative number if the net flux enters the cylnder. what is ex(p), the value of the x-component of the electric field produced by by the line of charge at point p which is located at (x,y) = (a,0), where a = 9.2 cm?
Physics
1 answer:
trasher [3.6K]3 years ago
8 0

Net flux through the cylindrical surface is given as

\phi = \frac{q}{epsilon_0}

here q = enclosed charge in the surface

so here in order to find the value of q

q = \lambda* L

so now we have

\phi = \frac{\lambda * L}{\epsilon_0}

so this is the total flux

now by Gauss's law we can find the electric field

\int E.dA = \phi

\int E.dA = \frac{\lambda * L}{\epsilon_0}

E* 2\pi rL = \frac{\lambda * L}{epsilon_0}

E = \frac{\lambda}{2\pi \epsilon_0 r}

<em>by above expression we can find the electric field at required position</em>

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This time particle A starts from rest and accelerates to the right at 65.5 cm/s
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