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devlian [24]
3 years ago
11

In a roller coaster, a car has X joules of potential energy when it is resting at the top of the hill. The car moves downhill an

d reaches the bottom of the hill, where it moves quickly. Assuming no friction, what does the law of conservation of energy predict about the car?
A)At the bottom, the car has X joules of potential energy.
B)At the bottom, the car has X joules of mechanical energy.
C)At the bottom, the car has more than X joules of kinetic energy.
D)At the bottom, the car has more than X joules of mechanical energy.
Physics
1 answer:
natita [175]3 years ago
4 0
"At the bottom, the car has X joules of mechanical energy" is the one among the following choices given in the question that <span>the law of conservation of energy predict about the car. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer helped you.</span>
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Answers:

a) 2.82(10)^{21} kg

b) 1410 J

c) 36.62 m/s

Explanation:

<h3>a) Mass of the continent</h3>

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Where:

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<h3>b) Kinetic energy of the continent</h3>

Kinetic energy K is given by the following equation:

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Where:

m=2.82(10)^{21} kg is the mass of the continent

v=4.8 \frac{cm}{year} \frac{1 m}{100 cm} \frac{1 year}{365 days} \frac{1 day}{24 hours} \frac{1 hour}{3600 s}=1(10)^{-9} m/s is the velocity of the continent

K=\frac{1}{2}(2.82(10)^{21} kg)(1(10)^{-9} m/s)^{2} (6)

K=1410 J (7) This is the kinetic energy of the continent

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If we have a jogger with mass m=77 kg and the same kinetic energy as that of the continent 1413 J, we can find its velocity by isolating v from (5):

v=\sqrt{\frac{2 K}{m}} (6)

v=\sqrt{\frac{2 (1413 J)}{77 kg}}

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v=36.62 m/s This is the speed of the jogger

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