Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Answer:
All of the above are true
Explanation:
Organisms possess two types of genome viz; prokaryotic genome and eukaryotic genome. The eukaryotic genome is possessed by cells with a well-defined nucleus, where their genetic material (DNA). The prokaryotic genome, on the other hand, lacks a membrane-bound nucleus. The major organization or content between these two genomes are:
- Prokaryotic genomes generally have less DNA and fewer genes than eukaryotic genomes.
- Prokaryotic genomes have fewer repeated sequences and noncoding, intragenic sequences than eukaryotic genomes.
- Most prokaryotic genomes are contained in one circular chromosome while most eukaryotic genomes are contained on several linear chromosomes.
- In general, eukaryotic genomes contain many introns, repeated sequences, and transposable elements.
Based on this, all of the above options are TRUE
When an acyl group is being transferred from the cytosol to the mitochondria for oxidation, the order of the enzymes it encounters is
CPT-I Carnitine Translocase : CPT -II
CPT-I and CPT-II are crucial for the beta-oxidation of long-chain fatty acids in the mitochondria by enabling their transport across the mitochondrial membrane.
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Answer:
Collaborative empiricism
Explanation:
Collaborative empiricism is based on establishing a therapeutic relationship which is becomes a partnership by which the therapist and patient work together as a team to identify maladaptive cognitions and behaviour, test their validity, and make revisions to the therapy if needed.
