Answer:
a) 0.0875A
b) 2.06*10^-6m/s
Explanation:
given
Diameter, d = 2.6mm = 0.0026m
Charge, Q = 420C
Time, t = 80mins = 80*60s = 4800s
Concentration of electrons, n = 5*10^28
To find the current, recall that q = it
Therefore, i = Q/t
Current, i = 420/4800
i = 0.0875A
To get the drift velocity, recall that I = n*q*Vd*A
A = πd²/4
A = π*0.0026²/4
A = 5.3*10^-6m²
Then, Vd = I/nqA
Vd = 0.0875/(5*10^28 * 1.6*10^-19 * 5.3*10^-6)
Vd = 0.0875/42400
Vd = 2.06*10^-6m/s
Note, low Vd causes low current.
Therefore, the current is 0.0875A and the Vd is 2.06*10^-6m/s
Weight = (mass) x (acceleration of gravity).
When I calculate the weight of the 81.6 kg, the number I use for gravity
is 9.807 m/s². That gives a weight of 800.25 N, so I think that's where the
question got the crazy number of 81.6 kg ... whoever wrote the problem
wants the hay to weigh 800 N, and that's what I'll use for the weight.
The forces on the bale of hay are gravity: 800N downward, and the
guy on the truck with the pitchfork pulling upward on it with 850 N.
The net force on the bale is (850 - 800) = 50 N upward.
Use Newton's second law of motion: (Net force) = (mass) x (acceleration)
Divide each side by 'mass' :
Acceleration = (net force)/(mass)
On the hay wagon,
Acceleration = (50 N upward) / (81.6 kg) = <em>0.613 m/s² upward</em>
Answer:
T = 8.19 s
, = 23 m / s
Explanation:
In the simple harmonic motion the equation that describes them is
y = A cos wt
Acceleration can be found by derivatives
a = d²y / dt²
v = dy / dt = - Aw sin wt
a= d²y / dt² = - A w² cos wt
For maximum acceleration cosWT = + -1
= -A w2
w = RA (/ A)
w = RA (1.8 9.8 / 30.0)
w = 0.767 rad / s
The angular velocity is related to the frequency
w = 2π f
f = 1 / T
w = 2π / T
T = 2π / w
T = 2π / 0.767
T = 8.19 s
For maximum speed the sin wt = + -1
= A w
= 30.0 0.767
= 23 m / s
Answer:
The magnitude of the torque is 263.5 N.
Explanation:
Given that,
Applied force = 31 N
Distance from the axis = 8.5 m
She applies her force perpendicularly to a line drawn from the axis of rotation
So, The angle is 90°
We need to calculate the torque
Using formula of torque
Where, F = force
d = distance
Put the value into the formula
Hence, The magnitude of the torque is 263.5 N.