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ale4655 [162]
2 years ago
11

Which two characteristics increase the strength of the gravitational force

Physics
1 answer:
snow_tiger [21]2 years ago
4 0

Answer:

The answer is A and C.

Explanation:

Only two factors are relevant when dealing with the gravitational force between two objects - their mass and their distance apart from one another. Gravity's force is proportional to the product of the masses of the two objects and is inversely proportional to the square of the distance between them.

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The speed of a wave is dependant on four factors: wavelength, frequency, medium, and temperature.
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What is mean by gravitational force​
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<u>Gravitational Force</u> is a force that attracks two objects with mass. For example, you are being pulled onto this planet, and that's why when you jump upwards, you fall back down quickly. A fun fact is that every object, even the entire universe, are pulling all on each other, including you!

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3 years ago
Fossil fuels are burned, transferring their chemical potential energy to heat energy. How are nuclear power stations different?
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Answer:

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Explanation:

6 0
3 years ago
Help me plz thanks you
andreev551 [17]
Acant help you because some letters are blocked out sorry.<span />
8 0
3 years ago
The speed of a wave on a violin A string is 288 m/s and on the G string is 128 m/s. The force exerted on the ends of the string
Katyanochek1 [597]

Answer:

\dfrac{\mu_A}{\mu_G}=0.197

Explanation:

given,

Speed of a wave on violin A = 288 m/s

Speed on the G string = 128 m/s

Force at the end of string G  = 110 N

Force at the end of string A = 350 N

the ratio of mass per unit length of the strings (A/G). = ?

speed for string A

 v_A = \sqrt{\dfrac{F_A}{\mu_A}}.......(1)

speed for string G

 v_G = \sqrt{\dfrac{F_G}{\mu_G}}........(2)

Assuming force is same in both the string

now,

dividing equation (2)/(1)

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\dfrac{F_G}{\mu_G}}}{\sqrt{\dfrac{F_A}{\mu_A}}}

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{128}{288}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{\mu_A}{\mu_G}=0.197

5 0
3 years ago
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