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weqwewe [10]
3 years ago
5

In which situation is the gravitational force between two objects hard to detect? (Options)

Physics
2 answers:
svlad2 [7]3 years ago
5 0

A - the objects are too small

GRAVITATIONAL FORCE IS EXPERIENCED BY ALL OBJECTS IN THE UNIVERSE ALL THE TIME. BUT THE ORDINARY OBJECTS YOU SEE EVERY DAY HAVE MASSES SO SMALL THAT THEIR ATTRACTION TOWARD EACH OTHER IS HARD TO DETECT. -https://www.ftsd.org/cms/lib6/MT01001165/Centricity/ModuleInstance/630/CHAPTER_2_NOTES_FOR_EIGHTH_GRADE_PHYSICAL_SCIENCE.pdf

Anit [1.1K]3 years ago
4 0

Answer:

Hence, the correct option is (A) "If the mass of each object is very small".

Explanation:

The gravitational force between two objects is directly proportional to the product of masses and inversely proportional to the square of the distance between them.

The mathematical expression is given by :

F=G\dfrac{m_1m_2}{d^2}

d is the distance between masses

Gravitational force is one of the fundamental force in the universe. If the masses of objects is too small, then their interaction with each other is hard to detect.

Hence, the correct option is (A) "If the mass of each object is very small".

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Answer:

a. \mathbf{F_{f_2} = 2 F_{f1}}, \mathbf { since \ the \ force \ o f \ friction  \ is \ represented  \ as  \ the \  slope \ for \ each  \ of  \ the \ two  \ curves.}

Explanation:

From the information given;

Using the work-energy theorem

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∴

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Then;

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3 years ago
A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it st
Morgarella [4.7K]

Answer:

<em> B.0</em>

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Let: M = m kg and V = U = v m/s

Substituting these values into equation 1

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Change in momentum = m(0)

Change in momentum = 0 kg.m/s

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