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d = 0.221 mm is the spacing (in mm) between the two slits..
here,
wavelength = 589 nm
D = 150 cm = 1.5 m
y = 4 mm
then ,
y = mλD/d
for m = `1
0.004 = 589*10^-9 * 1.5/d
d = 2.21*10^-4 m
d = 0.221 mm
slit spacing is 0.221 mm
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Answer:
The tension in the rod as the ball moves through the bottom circle is 9.8 N
Explanation:
When the ball is released from rest, the centripetal force equals the weight of the ball. So mv²/r = mg where m = mass of ball = 0.5 kg, v = speed of ball, r = radius of vertical circle = length of rod = 0.5 m and g = acceleration due to gravity = 9.8 m/s²
v = √gr = √9.8 m/s² × 0.5 m = √4.9 = 2.21 m/s
Now at the bottom of the circle T - mg = mv²/r where T = tension in the rod
T = m(g + v²/r)
= m(g + (√gr)²/r)
= m(g+ gr/r)
= m(g + g)
= 2mg
= 2 × 0.5 kg × 9.8 m/s²
= 9.8 N
So, the tension in the rod as the ball moves through the bottom circle is 9.8 N
False. Energy in any form is a scalar quantity.
