Answer:
The answer to your question is below
Explanation:
For the reaction N2 + 3H2 = 2NH3, if you have 2.00 moles of N2 and 4.00 moles of H2 : a. Identify the limiting reactant. ____________
N2 + 3H2 = 2NH3
1 mol 3 moles 2 moles
Given 2 moles 4 moles
Rule of three for N2
x = (2 x 3) / 1 = 6 mol of H2, it means that is needed 6 moles of H2 and there are only 4, so the limiting reactant is H2
b. How many moles of NH3 can be formed? ____________
rule of three
3 moles of H2 --------------------- 2 moles of NH3
4 moles of H2 --------------------- x
x = (4x2)/3 = 2.7 moles of NH3 are formed
c. How many moles of the excess reactant will remain? _________
x = (4 x 1) / 3 = 1.33
Excess reactant = 2 - 1.33 = 0.67 moles
Answer:
17.1 L
Explanation:
P1V1/T1 = P2V2/T2 T is in K
P1V1/T1 * T2/P2 = V2
735 * 7.31 / (45+273.15) * (55+ 273.15)/325 = V2
V2 = 17.1 L
Answer: The volume of sample at 400 K is 
Explanation:
Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
(At constant pressure and number of moles)
where,
= initial volume of gas = 
= final volume of gas = ?
= initial temperature of gas = 360 K
= final temperature of gas = 400 K
Putting in the values we get:
Thus volume of sample at 400 K is
as water is cooled it's density increases until about 4 c then it decreases
Explanation:
a) 3 sig. figures
b) 3 sig. figures
c) 6 sig. figures
d) 2 sig. figures
e) 1.09 × 104 = 113.36 = 5 sig. figures
if it is 1.09 × 10^4, it is 10900 = 3 sig. figures
f) 4 sig. figures
