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AlexFokin [52]
3 years ago
13

Which 10-milliliter sample of water has the greatest degree of disorder?A)H2O(g) at 120°CB)H2O() at 80°CC)H2O() at 20°CD)H2O(s)

at 0°C
Chemistry
1 answer:
AnnyKZ [126]3 years ago
6 0

Answer:

A) H₂O at 120°C

Explanation:

It is possible to think the higher temperature, the greatest degree of disorder. That is because with a high temperature, vibrations of molecules increases.

In general, at low temperatures, the molecules are in solid state (The lowest degree of disorder), increasing its temperature, molecules becomes in liquids, and, with more temperature, are gases (The greatest degree of disorder).

Thus, the sample that has the greatest degree of disorder is:

<h3>A) H₂O at 120°C</h3>
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Consider the reaction 2 NO + O2 → 2 NO2
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Answer:

(a) Rate at which NO_2 is formed is 0.050 M/s

(b) Rate at which O_2 is consumed is 0.0250 M/s.

Explanation:

The given reaction is:-

2NO+O_2\rightarrow 2NO_2

The expression for rate can be written as:-

-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}

Given that:- \frac{d[NO]}{dt}=-0.050\ M/s (Negative sign shows consumption)

-\frac{1}{2}\frac{d[NO]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}

-\frac{d[NO]}{dt}=\frac{d[NO_2]}{dt}

-(-0.050\ M/s)=\frac{d[NO_2]}{dt}

\frac{d[NO_2]}{dt}=0.050\ M/s

(a) Rate at which NO_2 is formed is 0.050 M/s

-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}

-\frac{1}{2}\times -0.050\ M/s=-\frac{d[O_2]}{dt}

\frac{d[O_2]}{dt}=0.0250\ M/s

(b) Rate at which O_2 is consumed is 0.0250 M/s.

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3 years ago
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