Answer:
Explanation:
Salicylic Acid:
Salicylic Acid is an hydroxy acid that is found as a natural compound in plants. It's IUPAC name is 2-hydroxybenzoic acid. Salicylic acid has an odorless white to light tan solid color. It sinks and mixes very slow with water.
Acid: An acid is a substance that produce hydrogen ion or proton when dissolved in water
Base: A base is a substance that will neutralize an acid to yield salt and water
Conjugate Base: This is a substance formed when an acid loses an hydrogen ion or proton when it dissolved in water.
Conjugate Acid: This is a substance formed when a base accept a proton from from any acid, when it dissolved in water.
Reaction between salicylic acid and potassium hydroxide
HOC₆H₄COOH(aq) + KOH(aq) ⇄ HOC₆H₄COOK(aq) + H₂O(l)
Acid ⇒ HOC₆H₄COOH (salicylic acid)
Base ⇒ KOH (potassium hydroxide)
Conjugate acid ⇒ H₂O (water)
conjugate base ⇒ HOC₆H₄COOK ( 2-hydroxypotasium benzoate)
•3.9g of ammonia
•molar mass of ammonia = 17.03g/mol
1st you have to covert grams to moles by dividing the mass of ammonia with the molar mass:
(3.9 g)/ (17.03g/mol) = 0.22900763mols
Then convert the moles to molecules by multiplying it with Avogadro’s number:
Avogadro’s number: 6.022 x 10^23
0.22900763mols x (6.022 x 10^23 molecs/mol)
= 1.38 x 10^23 molecules
Answer:
1.034 L
Explanation:
P1 V1 = P2 V2
P1 V1 / P2 = V2
2.4 (2.5) / 5.8 = V2 = 1.034 L
Answer:
The temperature difference of the body after 3 hours = 5.16 K
Explanation:
we know that the number of moles of O₂ inhaled are 0.02 mole/min⁻¹
or, 1.2 mole.h⁻¹
The average heat evolved by the oxidation of foodstuffs is then:
⇒ Q avg =
= 7.2 kj.h⁻¹.Kg⁻¹
the heat produced after 3 h would be:
= 7.2 kj. h⁻¹.Kg⁻¹ x 3 h
= 21.6 kj. kg⁻¹
= 21.6 x 10³ j kg⁻¹
We know Qp = Cp x ΔT
Assume the heat capacity of the body is 4.18 J g⁻¹K⁻¹
⇒ ΔT = 
⇒ ΔT = 
⇒ ΔT = 5.16 K
Answer:
Partial pressure of CO₂ is 406.9 mmHg
Explanation:
To solve the question we should apply the concept of the mole fraction.
Mole fraction = Moles of gas / Total moles
We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)
Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles
To determiine the partial pressure of CO₂ we apply
Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P
Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure
We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg
