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patriot [66]
3 years ago
5

Which of these particles are lost in the oxidation process? A. protons B. neutrons C. electrons D. atoms

Chemistry
2 answers:
vladimir2022 [97]3 years ago
7 0

C. electrons

Hope this helps.

irina [24]3 years ago
3 0

C. electrons

i took at test that had this question and this was the answer

brainliest plz

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An unknown liquid has a mass of 4.25 × 108 mg and a volume of 0.250 m3. what is the density of the liquid in units of g/ml?
mrs_skeptik [129]
Density= mass/volume
             step  one :
  convert  m3  to  ml
1m^3  =1000000ml
0.250m^3 x1000000=250000ml
         
           step  two:  convert  mg   to  g
 1mg=0.001g,  therefore 4.25 x108mg=0.459g
density  is  therefore= 0.459g/250000=1.836 x10^-6g/ml
8 0
3 years ago
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How many atp molecules are produced during the citric acid cycle?
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2 years ago
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A bottle of wine contains 9.81 grams of C2H5OH, dissolved in 87.5 grams of water. The final volume of the solution is 100.0 mL.
dimulka [17.4K]

Answer:

[EtOH] = 2.2M and Wt% EtOH = 10.1% (w/w)

Explanation:

1. Molarity = moles solute / Volume solution in Liters

=> moles solute = mass solute / formula weight of solute = 9.8g/46g·mol⁻¹ = 0.213mol EtOH

=> volume of solution (assuming density of final solution is 1.0g/ml) ...

volume solution =  9.81gEtOH + 87.5gH₂O = 97.31g solution x 1g/ml = 97.31ml = 0.09731 Liter solution

Concentration (Molarity) = moles/Liters = 0.213mol/0.09731L = 2.2M in EtOH

2. Weight Percent EtOH in solution (assuming density of final solution is 1.0g/ml)

From part 1 => [EtOH] = 2.2M in EtOH = 2.2moles EtOH/1.0L soln

= {(2.2mol)(46g/mol)]/1000g soln] x 100% = 10.1% (w/w) in EtOH.

3 0
3 years ago
Why there are only seven crystal systems??? why not other number
Anastasy [175]
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6 0
3 years ago
2C2H2 + 5O2 → 4CO2 + 2 H2O How many grams of CO2 are required to react with exactly 3.00 mol of O2? 106 g 132 g 165 g 76.8 g
cricket20 [7]

Hey there!:

Given the reaction:

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

5 moles O2 ------------- 4 moles CO2

3.00 moles O2 ----------  ( moles of CO2 ?? )

moles of CO2 = 3.00 * 4 / 5

moles of CO2 =  12 / 5

moles of CO2 = 2.4 moles

So, molar  mass CO2 = 44.01 g/mol

Therefore:

1 mole CO2 -------------- 44.01 g

2.4 moles CO2 ---------- ( mass of CO2 )

mass of CO2 = 2.4 * 44.01 / 1

mass of CO2 = 106 g

Answer A


Hope that helps!

8 0
3 years ago
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