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olasank [31]
3 years ago
11

What type of solution is formed when steam from boiling water evaporates into the air

Chemistry
1 answer:
Hoochie [10]3 years ago
7 0
That specific kind is called gas.

When you put water in a freezing temprature it becomes solid.
When you boil water it becomes gas
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Which of the following is an example of a chemical change? Dissolving sugar in coffee Evaporating rubbing alcohol Freezing water
Sholpan [36]

Rusting iron is an example of a chemical change because iron reacts with air when moisture is present.

examples of chemical changes are:

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• Can be production of flames

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Examples of physical changes are:

• Melting

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3 0
3 years ago
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What is the chemical symbol for fluoride
sweet [91]

Answer:  

I think F

Explanation:

4 0
3 years ago
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How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 6.46 atm and 45°C in the reaction shown below?
ankoles [38]
The chemical reaction equation for this is 

XeF6 + 3H2 ---> Xe + 6HF

Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.

we get n = 0.1433 moles H2

to get the mass of XeF6, 

we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.

0.1433 moles H2 x \frac{1 mole XeF6}{3 moles H2} x \frac{245.28 g XeF6}{1 mole XeF6} = 11.71 g XeF6

Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.
3 0
3 years ago
Heating a substance____the speed at which molecules move
guapka [62]

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Heating a substance increases the speed at which molecules move.

Explanation:

4 0
3 years ago
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What is the boiling point of a 1.5 m aqueous solution of fructose? the boiling point elevation constant of water is 0.515°c/m.
GREYUIT [131]
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.<span>
ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
 Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
5 0
3 years ago
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