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vredina [299]
3 years ago
12

I need help with this problem !

Chemistry
1 answer:
Sloan [31]3 years ago
7 0

Answer:

3

Explanation:

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Use stoichiometry 3.75moles k* 39.10g k\1 mole k= 146.63g k
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Compared with the freezing-point depression of a 0.01 m c6h12o6 solution, the freezing-point depression of a 0.01 m nacl solutio
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Answer:

Twice  as much.

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0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.

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1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).

That's 0.02 mol of particles, so the freezing point depression of 0.01 mol·L⁻¹ NaCl will be twice that of 0.01 mol·L⁻¹ C₆H₁₂O₆.

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4 years ago
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<span>0.4 N</span>

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