A) -0.5(9.8)*t^2 = -25(t-2) - 0.5(9.8)(t-2)^2
-4.9t^2 = -25t + 50 - 4.9(t^2-4t+4)
0 = -25t+50+19.6t - 19.6
5.4t = 30.4
t = 5.62962963 s
b) h = -4.9(5.62962963)^2
h = -155.2943759
the building is 155.2943759 m high
c) speed 0of first stone
= at
= 9.8*5.62962963
= 55.17037037 m/s
speed of second stone
= v + at
= 25+9.8*3.62962963
= 60.57037037 m/s
Answer:
M = 1.26
Explanation:
Molarity = mole of solution/liters of solution
435mL/1000 = .435L
Plugging in the numbers into the formula, we get:
Molarity = .550 mol/.435L = 1.26 M
Answer:
The water lost is 36% of the total mass of the hydrate
Explanation:
<u>Step 1:</u> Data given
Molar mass of CuSO4*5H2O = 250 g/mol
Molar mass of CuSO4 = 160 g/mol
<u>Step 2:</u> Calculate mass of water lost
Mass of water lost = 250 - 160 = 90 grams
<u>Step 3:</u> Calculate % water
% water = (mass water / total mass of hydrate)*100 %
% water = (90 grams / 250 grams )*100% = 36 %
We can control this by the following equation
The hydrate has 5 moles of H2O
5*18. = 90 grams
(90/250)*100% = 36%
(160/250)*100% = 64 %
The water lost is 36% of the total mass of the hydrate
Answer:
The answer to your question is 0.10 M
Explanation:
Data
Molarity = ?
mass of Sucrose = 125 g
volume = 3.5 l
Formula
Molarity = moles / volume
Process
1.- Calculate the molar mass of sucrose
C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)
= 144 + 22 + 176
= 342 g
2.- Convert the mass of sucrose to moles
342 g of sucrose ------------------- 1 mol
125 g of sucrose -------------------- x
x = (125 x 1) / 342
x = 0.365 moles
3.- Calculate the molarity
Molarity = 0.365 / 3.5
4.- Result
Molarity = 0.10
