Answer:
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Explanation:
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Answer:
Original temperature (T1) = - 37.16°C
Explanation:
Given:
Gas pressure (P1) = 2.75 bar
Temperature (T2) = - 20°C
Gas pressure (P2) = 1.48 bar
Find:
Original temperature (T1)
Computation:
Using Gay-Lussac's Law
⇒ P1 / T1 = P2 / T2
⇒ 2.75 / T1 = 1.48 / (-20)
⇒ T1 = (2.75)(-20) / 1.48
⇒ T1 = -55 / 1.48
⇒ T1 = - 37.16°C
Original temperature (T1) = - 37.16°C
Answer:
Brown color of the solution decreases
Explanation:
is brown in color whereas 
is colorless.
Equilibrium reaction between and is as follows:
As per the Le Chatelier's principle, if pressure of a equilibrium is increased, the equilibrium will shift in the direction having fewer no. of moles of gases.
In the given equilibrium, side has more no. of moles. So on increasing pressure, equilibrium will shift towards the side of or more formation of will take place.
Therefore, more will decompose that will decrease the brown color of the solution as is colorless.
Answer:
• The actual number of moles of each element in the smallest unit of the compound. •In water (H 2 O), ammonia (NH 3), methane (CH 4), and ionic compounds, the empirical and molecular
Explanation:
You take the grams of CO₂ times Avogadro's number divided by the molar mass.
