C. ionization reaction...
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(A) Na2CO3
(B) NaHCO3
(C) H2CO3
(D) HF
(E) SO3
(F) CuSO4
(G) H2SO4
(H) H2S
- Remember to place the subscripts correctly. Hope I helped.
The type of bond connects the fatty acid will be " an ester bond".
Fatty acids could be joined to each of the three carbons of the glycerol molecule in a fat molecule by an ester bond that passes through into the oxygen atom. Three molecules are emitted during the establishment of the ester bond. Fats were also known as triacylglycerols as well as triglycerides because they are made consisting of three fatty acids and glycerol.
The three major nutrients in a diet may be carbohydrates, proteins, and fats. According to how many hydrogen bonds they contain, fats are classified as either saturated as well as unsaturated.
The type of bond connects the fatty acid will be " an ester bond".
Hence, the correct answer will be option (c)
To know more about fatty acid
brainly.com/question/13528495
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They all share the same atomic number (number of protons)
Answer:
9.42g/cm3
Explanation:
Data obtained from the question include the following:
Mass of the metal = 24.50g
Volume of metal = 2.6 ml = 2.6cm3
Density =..?
The density of a substance is defined by the mass of the substance per unit volume of the substance. It is represented mathematically as:
Density = Mass /volume
With the above formula, we can obtain the density of the metal as follow:
Density = Mass/volume
Density = 24.50g/2.6cm3
Density = 9.42g/cm3