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Katarina [22]
3 years ago
5

If an atom has an electron in the n = 4 state with ml = 2, what are the possible values of l?

Chemistry
1 answer:
Pavel [41]3 years ago
4 0

Answer:

The possible values of l are 2 and 3

Explanation:

Each electrons have four quantum numbers:

  • n: the principal quantum number, which value matches with the energy level of the electron.
  • l: the secondary quantum number, which value can be from 0 to n-1
  • m: the magnetic number, which value can be from -l to l
  • sp: the spin number which value can be -1/2 or +1/2

In this case, n=4 so the values of l are:

l=0, 1, 2, 3

Now, if:

  • l=0 the value of m is m=0
  • l=1 the values of m are m= -1, 0, 1
  • l=2 the values of m are m= -2, -1, 0, 1, 2
  • l=3 the values of m are m= -3, -2, -1, 0, 1, 2, 3

Being all that said, l can be either  equal to 2 or 3

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Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

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% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

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