Determine a detailed mechanism for the chlorination of benzene using cl2 and fecl3.
1 answer:
Step (1):
Generation of electrophile: by the action of Lewis acid FeCl₃ on Cl₂ to serve as a source of Cl⁺ (Electrophile)
Step (2):
Addition of electrophile to form carbocation:
addition of electrophile to form C-Cl bond and form carbocation which is stabilized by resonance.
Step (3):
Loss of proton to re-form the aromatic ring by the action of FeCl₄⁻ which removes proton from carbon containing Cl and forming the aromatic ring again
Generation of electrophile: by the action of Lewis acid FeCl₃ on Cl₂ to serve as a source of Cl⁺ (Electrophile)
Step (2):
Addition of electrophile to form carbocation:
addition of electrophile to form C-Cl bond and form carbocation which is stabilized by resonance.
Step (3):
Loss of proton to re-form the aromatic ring by the action of FeCl₄⁻ which removes proton from carbon containing Cl and forming the aromatic ring again
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Answer:
The forward reaction is occurring at a faster rate than the reverse reaction.
Explanation:
Reaction quotient (Q) of the given reaction is -
where [NO], and
represents concentrations of respective species at a certain time.
Here = 0.80 M,
= 0.050 M and [NO] = 0.10 M
So,
Hence
It means that forward reaction is faster than reverse reaction at that point. Because then only concentration of NO is higher than concentrations of and
which makes Q higher than K.