Determine a detailed mechanism for the chlorination of benzene using cl2 and fecl3.
1 answer:
Step (1):
Generation of electrophile: by the action of Lewis acid FeCl₃ on Cl₂ to serve as a source of Cl⁺ (Electrophile)
Step (2):
Addition of electrophile to form carbocation:
addition of electrophile to form C-Cl bond and form carbocation which is stabilized by resonance.
Step (3):
Loss of proton to re-form the aromatic ring by the action of FeCl₄⁻ which removes proton from carbon containing Cl and forming the aromatic ring again
Generation of electrophile: by the action of Lewis acid FeCl₃ on Cl₂ to serve as a source of Cl⁺ (Electrophile)
Step (2):
Addition of electrophile to form carbocation:
addition of electrophile to form C-Cl bond and form carbocation which is stabilized by resonance.
Step (3):
Loss of proton to re-form the aromatic ring by the action of FeCl₄⁻ which removes proton from carbon containing Cl and forming the aromatic ring again
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Answer:
200/3 M which is approximately equal to 66.6667 M
Explanation:
Molarity is defined as the number of moles of solute per liter of solution.
It can be calculated as follows:
We are given that:
number of moles of solute = 8 moles
volume of solution = 120 ml = 0.12 liters
Substitute with the givens in the above equation to get the molarity as follows:
molarity =
Hope this helps :)
200/3 M which is approximately equal to 66.6667 M
Explanation:
Molarity is defined as the number of moles of solute per liter of solution.
It can be calculated as follows:
We are given that:
number of moles of solute = 8 moles
volume of solution = 120 ml = 0.12 liters
Substitute with the givens in the above equation to get the molarity as follows:
molarity =
Hope this helps :)