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Anon25 [30]
3 years ago
13

In Males which of the following organ performs a dual function of ejaculation of sperm and voiding of urine

Chemistry
2 answers:
Nat2105 [25]3 years ago
5 0

Answer: Urethra

Explanation:

The urethra is a tube like structure which performs the function of excretion as well as copulation. It carries the urine stored inside the bladder to the outside the body. During copulation, the semen is ejected from the urethra inside the female external genitalia that is vaginal canal. The urethra prevents the flow of urine and it just allows the ejaculation of semen during copulation.

Anna11 [10]3 years ago
3 0
I believe it is the urethra 
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A phosphate buffer solution (25.00 mL sample) used for a growth medium was titrated with 0.1000 M hydrochloric acid. The compone
AysviL [449]

Answer:

0,07448M of phosphate buffer

Explanation:

sodium monohydrogenphosphate (Na₂HP) and sodium dihydrogenphosphate (NaH₂P) react with HCl thus:

Na₂HP + HCl ⇄ NaH₂P + NaCl <em>(1)</em>

NaH₂P + HCl ⇄ H₃P + NaCl <em>(2)</em>

The first endpoint is due the reaction (1), When all phosphate buffer is as NaH₂P form, begins the second reaction. That means that the second endpoint is due the total concentration of phosphate that is obtained thus:

0,01862L of HCl×\frac{0,1000mol}{L}= 1,862x10⁻³moles of HCl ≡ moles of phosphate buffer.

The concentration is:

\frac{1,862x10^{-3}moles}{0,02500L} = <em>0,07448M of phosphate buffer</em>

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I hope it helps!

7 0
4 years ago
Rick is creating a love potion for Morty. To make the potion, Rick's needs 51 mL of a mixture solution where 40% is carbonated w
Deffense [45]

Answer:

The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL

Explanation:

So as to make the love potion, we have;

The percentage of carbonated water in the love portion = 40%

The percentage of green tea in the first solution = 65%

The percentage of carbonated water in the first solution = 15%

The percentage of whole milk in the first solution = 20%

The percentage of orange juice in the second solution = 17%

The percentage of lemonade in the second solution = 38%

The percentage of carbonated water in the second solution = 45%

Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;

x + y = 51...(1)

0.15·x + 0.45·y = 0.40×51 = 20.4

0.15·x + 0.45·y = 20.4...(2)

Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;

For equation (1)

y = 51 - x

For equation (2)

y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x

y = 136/3 - (1/3)·x

Equating the two equations of 'y', gives;

51 - x = 136/3 - (1/3)·x

51 - 136/3 = x - (1/3)·x

17/3 = (2/3)·x

(2/3)·x = 17/3

x = (3/2) × (17/3) = 17/2 = 8.5

x = 8.5

y = 51 - x = 42.5

y = 42.5

Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL

8 0
3 years ago
How many grams of water would require 2200 joules of heat to raise it’s temperature from 34 degrees Celsius to 100 degrees celsi
Arada [10]

Answer:

Mass, m = 7.97 grams

Explanation:

We have,

Initial temperature was 34 degrees Celsius

Heat produced in it is 100 calories of heat

The specific heat capacity of water is 4.18 J/g °C

The heat produced due to change in temperature is given by :

Q=mc(T_f-T_i)

m is mass of water in grams

m=\dfrac{Q}{c(T_f-T_i)}\\\\m=\dfrac{2200}{4.18\times (100-34)}\\\\m=7.97\ g

So, 7.97 grams of water is required to produce heat of 2200 joules.

7 0
3 years ago
The letter "p" indicates the ____.
earnstyle [38]
THE ANSWER IS .B. ORBITAL SHAPE
4 0
3 years ago
I WILL GIVE BRAINLIEST!!!!
Alona [7]
A. Atomic radius increases
7 0
3 years ago
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