I think its A. it cant be C or D b/c we are measuring the distance between Earth and Saturn, not the speed.
Answer: The dangers are decompression sickness arterial air embolism, and of course drowning. There are also effects of diving, such as nitrogen narcosis, that can contribute to the cause of these problems. And sea creatures like Great White Sharks, Lionfish, Sea snakes, Cone Snail, rays, The great barracuda, Flower Urchin, Stonefish, Blue Ringed Octopus. And more
Answer:a) Mass of 
in mixture = 26.3 grams
b) Mass of 
in mixture that can be recovered= 21.5 grams
Explanation:
Given :
Total Pressure = pressure of krypton + pressure of carbon dioxide = 0.751 atm
pressure of krypton = 0.231 atm
Thus pressure of carbon dioxide = 0.751 - 0.231 =0.52 atm
As we know:
where,
= partial pressure
= total pressure = 0.751 atm
= mole fraction
For
For
Total mass = Mass of + Mass of krypton = 30.8 + 25.2 = 56 g
Percentage of 
a) Thus Mass of in mixture =
Percentage of 
b) Thus Mass of in mixture that can be recovered=
Answer:
3–heptene or Hept–3–ene.
Explanation:
To name the compound given in the question above, we must determine the following:
1. Identify the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached to the compound.
4. Locate the position of the double bond (i.e the functional group) by giving it the lowest possible count.
5. Combine the above to obtain the name of the compound.
Now, we shall obtain the name of the compound as follow:
1. The compound contains double bond. Hence the compound is an alkene.
2. The longest continuous carbon chain is 7 i.e heptene.
3. No substituent group is attached to the compound.
4. The double bond is located at carbon 3 since counting from the right gives the lowest count for the double bond.
5. The name of the compound is:
3–heptene or Hept–3–ene
Answer
Explanation
We need a conversion factor that will converts from moles of glucose, C6H12O6 to molecules of glucose.
That is, one mole of any substance contains 6.022 x 10²³ molecule of that substance.
1.5055 x 10^24 molecules of glucose are in 2.5 moles of glucose C6H12O6
