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lianna [129]
3 years ago
15

A sample of oxygen gas was found to effuse at a rate equal to two times that of an unknown gas. The molecular weight of the unkn

own gas is ________ g/mol.
Chemistry
1 answer:
Pie3 years ago
6 0

Answer: 128 g/mol

Explanation:

Graham's law states that  the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.

Mathematically, that is:

\frac{Rate_1}{Rate_2}=\sqrt{\frac{MolarMass_2}{MolarMass_1} }

Since, you know the ratio of two rates and the molar mass of one gas, you can calculate the molar mass of the other gas.

The molar mass of the oxygen molecule, O₂ = 2×16.0g/mol = 32.0 g/mol.

In the coming equations, I will use 32 g/mol for simplicity of writing.

\frac{Rate_1}{Rate_2}=2 \\ \\ \\ MolarMass_1=32g/mol\\\\\\ 2=\sqrt{\frac{MolarMass_2}{32g/mol} } \\ \\ \\ 4=\frac{MolarMass_2}{32g/mol}\\ \\ \\ MolarMass_2=128g/mol

So, the molecular mass of the unnknown gas is 128 g/mol.

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The predominant greenhouse gas produced by human use of fossil fuels is __________. View Available Hint(s) The predominant green
mario62 [17]

Answer:

carbon dioxide

Explanation:

Carbon dioxide -

The gas carbon dioxide has a molecular formula of CO₂ ,

During the burning process of the fossil fuels , carbon dioxide is resealed in numerous amount , which act as a greenhouse gas .

Greenhouse gas - Are the gases which absorbs and release radiation , and are responsible for the greenhouse effect .

The greenhouse gases are - carbon dioxide , water vapor , methane , ozone , nitrous oxide .

6 0
2 years ago
4.41 g of propane gas (C3H8) is injected into a bomb calorimeter and ignited with excess oxygen, according to the reaction below
gayaneshka [121]

Answer :  The heat of the reaction is -221.6 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter

q_{rxn}=-q_{cal}

q_{cal}=c_{cal}\times \Delta T

where,

q_{rxn} = heat released by the reaction = ?

q_{cal} = heat absorbed by the calorimeter

c_{cal} = specific heat of calorimeter = 97.1kJ/^oC=97100J/^oC

\Delta T = change in temperature = (T_{final}-T_{initial})=(27.282-25.000)=2.282^oC

Now put all the given values in the above formula, we get:

q_{cal}=(97100J/^oC)\times (2.282^oC)

q_{cal}=221582.2J=221.6kJ

As, q_{rxn}=-q_{cal}

So, q_{rxn}=-221.6kJ

Thus, the heat of the reaction is -221.6 kJ

6 0
3 years ago
A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of
mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.125

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.125=e^{-0.00440\times t}

t = 473 year

8 0
3 years ago
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Elza [17]

Answer:

with what?

Explanation:

3 0
3 years ago
Permafrost soil (gelisol) is _______.
kvasek [131]
Permafrost soil (gelisol) is b) fragile. 
7 0
3 years ago
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