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3 years ago

NEED HELP FAST I WILL MARK BRAINLIEST AND THANK YOU AND RATE 5 STARS.

Chemistry

2 answers:

sleet_krkn [62]3 years ago

5 0

Hello there,

All compounds of carbon are made by ionic bonding.

I Hope this helps.

~Jurgen

Lyrx [107]3 years ago

4 0

All compounds of carbon are made by ionic bonding...
hope i helped!!!

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Calculate the energy in joules and calories required to heat 25.0 g of water from 12.5C to 25.7C

Alex Ar [27]

The heat (Q) required to raise the temp of a substance is:Q=m∗Cp∗ΔT where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
and Dt is the change in temp.
You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.
1380.72 Joules

8 0

3 years ago

A balloon is floating around outside your window. The temperature outside is 21 ∘C , and the air pressure is 0.700 atm . Your ne

Andreyy89

Answer:

$V=162L$

Explanation:

Hello,

In this case, we can compute the required volume by using the ideal gas equation as shown below:

$PV=nRT$

Thus, solving for the volume and considering absolute temperature (in Kelvins), we obtain:

$V=\frac{nRT}{P}= \frac{4.70mol*0.082\frac{atm*L}{mol*K}*(21+273)K}{0.700atm} \\\\V=162L$

Best regards.

4 0

3 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

What do all ions have in common in terms of their electrical structure?????

Free_Kalibri [48]

Answer:

The ratio between protons to electrons is not 1:1

Explanation:

A normal atom will be neutral in charge having 1 electron for each atom. An Atom that gains or looses an electron loses that perfect ratio. It is positive is electrons are loss and negative if electrons are gained.

3 0

3 years ago

For each scenario, determine if the electron has absorbed energy or emitted energy,

k0ka [10]

Answer:

1) emitted energy

2)absorbed energy

3)absorbed energy

4)emitted energy

Explanation:

I just got it right

7 0

3 years ago

Read 2 more answers