With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
<h3>What is the surface area of a truncated prism?</h3>
The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:
A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)
A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²
A = 276 cm²
With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
To learn more on surface areas: brainly.com/question/2835293
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Thousands grou
the thousands group. 913,256 256 being the ones group 913 being the thousands group. the name of the period with 913, is the thousands group p
For the first one EF is 119 degrees now since that's made with two radii it makes a central angle so whatever that arc is the central angle will be the same. fro the second one since SRQ is 52 degrees you just take that and subtract it from 180 to get SQ. I'm not quite sure about the third one. the forth you are taking the measurement of the arc its connected to and dividing that by 2 so it would be 71 degrees. I'm pretty sure in right.
<span>erry starts rowing at 2 pm from the west end of the lake, and Tao starts rowing from the east end of the lake at 2:05 pm.
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Terry DATA:
rate = 60 meter/min ; time = x min ; distance = r*t = 60x meters
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Tao DATA:
rate = 40 meter/min ; time = x-5 min ; distance = r*t = 40(x-5) meters
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If they always row directly towards each other at what time will the two meet?
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Equation:
dist + dist = 2000 meters
60x + 40(x-5) = 2000
20x = 1800
x = 90 minutes
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