Question

Consider the following reaction. What is the conjugate base of CH3COOH

Answer 1

Answer:

CH3COO–

Explanation:

its the answer

Answer 2

According to Bronsted-Lowry theory of acids and bases, an acid is proton donor and a base is proton acceptor. When an acid loses the proton, it forms the conjugate base of the acid. Similarly when a base accepts a proton, it forms the conjugate acid if that base. A conjugate acid base pair differs by a single proton.

Given the weak acid $CH_{3}COOH$. It can lose a proton to form the conjugate base.

$CH_{3}COOH(aq)-->CH_{3}COO^{-}(aq)+H^{+}(aq)$

Therefore, the conjugate base of $CH_{3}COOH$is $CH_{3}COO^{-}$.