Final setup in scientific method

Oxygen gas, generated by the reaction 2KClO3(s)---2KCl(s)+3O2(g), is collected over water at 27•C in 3.72L vassel at a total pre

Julli [10]

Answer:

moles = 0.093 moles

Explanation:

In this case, we know that this reaction is taking plave in a vessel that has a 730 torr of total pressure.

The total pressure is a value obtained by:

Pt = Pwater + PO2

We need to know the pressure of O2, because then, with stoichiometry, we can calculate the moles of KClO3

The pressure of oxygen is:

PO2 = 730 - 26 = 704 Torr

Now, this pressure is in Torr, and we need to convert it to Atm, so:

704 Torr / 760 Torr = 0.9263 atm

Now, let's use the ideal gas equation:

PV = nRT

With this expression, we will calculate the moles of O2, and then, the moles of KClO3:

n = PV/RT

R = 0.082 L atm /K mol

P = 0.9263 atm

V = 3.72 L

T = 27 + 273 = 300 K

Replacing the data:

n = 0.9263 * 3.72 / 300 * 0.082

n = 0.14 moles

Finally, by stoichiometry, we know that 2 moles of KClO3 produces 3 moles of O2, so:

moles of KClO3 = 0.14 * 2/3 = 0.093 moles of KClO3

6 0

2 years ago

What is the balanced chemical equation when an aqueous solution of calcium hydroxide reacts with liquid water?

Dmitrij [34]

Explanation:

Equation for Calcium Hydroxide Dissolving in Water | Ca(OH)2 + H2O

7 0

2 years ago

At 20°C the vapor pressure of benzene (C6H6) is 75 torr, and that of toluene (C7H8) is 22 torr. Assume that benzene and toluene

valina [46]

Answer: The mole fraction of benzene will be 0.34 and mole fraction of toluene is 0.66

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

$p_1=x_1p_1^0$ and $p_2=x_2P_2^0$

where, x = mole fraction in solution

$p^0$ = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_1+p_2\\$ $p_{total}=x_{benzene}p_{benzene}^0+x_{toluene}P_{toluene}^0$

$x_{benzene}=x$ ,

$x_{toluene}=1-x_{benzene}=1-x$ ,

$p_{benzene}^0=75torr$

$p_{toluene}^0=22torr$

$p_{total}=40torr$

$40=x\times 75+(1-x)\times 22$

$x=0.34$

Thus (1-x0 = (1-0.34)=0.66

Thus the mole fraction of benzene will be 0.34 and that of toluene is 0.66

8 0

3 years ago

`Let's just consider the concept of stoichiometry without any confusing chemicals. Here is a generic equation: 2A + 6B ? 3C. If

lesya [120]

Answer:

Option D. 5.5

Explanation:

The equation is this:

2A + 6B ⇒ 3C

With the amounts that we were given, let's determine which is the <em>limting reactant</em>

2 A reacts with 6 B

4 A will react with ( 4 .6)/2 = 12B

I have 11 B, so the limiting is B

6 B react with 2 A

11 B will react with (11 .2 )/6 =3.66 A

I have 4 A, so A is the excess.

6 B produce 3 C

11 B will produce ( 11 .3)/6 = 5.5C

7 0

3 years ago

A mixture of 2.0 L of hydrogen and 2.0 L of oxygen at the same temperature and pressure react to form the theoretical yield of w

otez555 [7]

Answer:

not sure, but you know what?

Explanation:

you are amazing! keep doing what youre doing!

7 0

3 years ago