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3 years ago

Please help i dont understand!

Physics

1 answer:

coldgirl [10]3 years ago

4 0

Answer:

100 m/s

Explanation:

SI units of distance and time are meters and seconds. km and hours are derived units. To express speed in SI units, it must be expressed as meters per second.

360 km/h = 100 m/s

_____

There are 3600 seconds in 1 hour, so 1 m/s = 3600 m/h = 3.6 km/h.

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When a dielectric slab is inserted between the plates of one of the two identical capacitors

tatiyna

Answer:(A-P,S;B-P,S;C-Q,S;D-P,S)

Solution

(A)→P,S,(B)→P,S,(C)→Q,S,(D)→P,S.

Explanation:

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2 years ago

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What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k

Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

$\sf \: F=ma$

Where,

F is force
m is mass
a is acceleration

In our case,

F = ?
m = 2500 kg
a = 20m/s

$\tt \: F_{net} = 2500 \times 20 \\ \tt= 50000$

Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~

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2 years ago

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Collapse question part Part 4 (d) What is the unit vector in the direction of the spacecraft's velocity? (Express your answer in

Maksim231197 [3]

Answer:

unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]

Explanation:

Given:

v = (-23.2, -104.4, 46.4) m/s

Above expression describes spacecraft's velocity vector v.

Find:

Find unit vector in the direction of spacecraft velocity v.

Solution:

Step 1: Compute magnitude of velocity vector.

mag (v) = sqrt ( 23.2^2 + 104.4^2 + 46.4^2)

mag (v) = 116.58 m/s

Step 2: Compute unit vector unit (v)

unit (v) = vec (v) / mag (v)

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3 years ago

Find the fundamental frequency and the next three frequencies that could cause standing-wave patterns on a string that is 30.0 m

maksim [4K]

Answer:

0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz

Explanation:

The fundamental frequency of a standing wave on a string is given by

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension in the string

$\mu$ is the mass per unit length

For the string in the problem,

L = 30.0 m

$\mu=9.00\cdot 10^{-3} kg/m$

T = 20.0 N

Substituting into the equation, we find the fundamental frequency:

$f=\frac{1}{2(30.0)}\sqrt{\frac{20.0}{(9.00\cdot 10^{-3}}}=0.786 Hz$

The next frequencies (harmonics) are given by

$f_n = nf$

with n being an integer number and f being the fundamental frequency.

So we get:

$f_2 = 2 (0.786 Hz)=1.572 Hz$

$f_3 = 3 (0.786 Hz)=2.358 Hz$

$f_4 = 4 (0.786 Hz)=3.144 Hz$

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3 years ago

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3 years ago

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