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Mariana [72]
3 years ago
12

What is gluteus maximum

Physics
2 answers:
kramer3 years ago
8 0
Any of three muscles in each buttock that move the thigh, the largest of which is the gluteus maximus
Orlov [11]3 years ago
5 0
Any of three muscles in each buttock that move the thigh, the largest of which is the gluteus maximus.
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Hi i was wondering if you could help me understand Kelvins? My question on my work says "Which of the following is the SI unit u
Pepsi [2]

Answer:

Hey there!

Kelvin is correct. Farenheit and Celsius are scales derived from the Kelvin scale. For example, K=C+273.15 is the conversion between Kelvin and Celsius.

Let me know if this helps :)

7 0
3 years ago
A rock is dropped from a bridge. What happens
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When a rock is dropped from a bridge in this way, in terms of the magnitude of the acceleration and the speed of the rock as it falls, the best option is "<span>(1) Both acceleration and speed increase."</span>
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3 years ago
A 0.71 W point source emits sound waves isotropically. Assuming that the energy of the waves is conserved, find the intensity (a
sveticcg [70]

Answer:

(a) 2.88×10⁻² W/m²

(b) 8.36×10⁻³ W/m²

Explanation:

The intensity of sound from an isotropic point source, with distance L is given as

I = P/(4πL²) .................................... Equation 1

Where I = intensity of sound, P = Power from the source, L = length, π = pie.

(a)

1.4 m from the source.

I = P/(4πL²)

Given: P = 0.71 W, L = 1.4 m, π = 3.14.

Substitute into equation 1

I = 0.71/(4×3.14×1.4²)

I = 0.71/24.6176

I = 0.0288 W/m².

I = 2.88×10⁻² W/m²

(b) 2.6 m from the source.

Given: P = 0.71 W, L = 2.6 m, π = 3.14

Substitute into equation 1

I = 0.71/(4×3.14×2.6²)

I = 0.71/84.9056

I = 0.00836 W/m²

I = 8.36×10⁻³ W/m²

5 0
4 years ago
A tray containing 0.20kg of water at 20degree celsius is placed in a freezer. The temperature of the water drops to 0degree cels
Nitella [24]

Answer:

a. Energy lost, Q = 16,800 Joules.

b. Power = 28 J/s

c. Time, t = 2357.14 seconds

d. I assumed that the ice remained at a temperature of zero degrees Celsius (0°C). Also, I assumed that the heat is being lost at a constant rate.

Explanation:

<u>Given the following data;</u>

  • Mass = 0.20 kg
  • Initial temperature, T1 = 20°C
  • Final temperature = 0°C
  • Time = 10 minutes

a. To find the energy lost by the water as it cools to 0 degree celsius;

Mathematically, heat capacity is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • M represents the mass of an object.
  • C represents the specific heat capacity of water.
  • dt represents the change in temperature.

dt = T2 - T1

dt = 20 - 0

dt = 20°C

We know that the specific heat capacity of water is equal to  4200 J/kg°C

Substituting the values into the formula, we have;

Q = 0.20 * 4200 * 20

<em>Energy lost, Q = 16,800 Joules.</em>

b. To find the average rate at which the water is losing energy in J/s by using the following formula;

Power = \frac {energy}{time}

First of all, we would have to convert the value of time in minutes to seconds.

<u>Conversion:</u>

1 minute = 60 seconds

10 minutes = X seconds

Cross-multiplying, we have;

X = 60 * 10

X = 600 seconds

Substituting the values into the formula, we have;

Power = \frac {16800}{600}

<em>Power = 28 J/s</em>

c. To estimate the time taken for the water at 0 degree celsius to turn completely into ice;

We know that the latent heat of fusion of water is equal to 3.3 * 10⁵ J/kg.

Mathematically, the latent heat of fusion is calculated by using the formula;

Energy, Q = ml = pt

Substituting the values into the formula, we have;

0.20 * 3.3 * 10⁵ = 28 * t

0.20 * 330000 = 28t

66000 = 28t

t = \frac {66000}{28}

<em>Time, t = 2357.14 seconds.</em>

d. The assumption made is that, the ice remained at a temperature of zero degrees Celsius (0°C). Also, I assumed that the heat is being lost at a constant rate.

6 0
3 years ago
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