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Alex
3 years ago
9

Question 4 of 10 Which three components define a person's overall health? A. Mental and emotional health B. Social health C. Phy

sical health D. Public health​
Physics
1 answer:
igomit [66]3 years ago
3 0

Answer:

physical, social, and mental

Explanation:

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A 1200 kg car accelerates from 13m/s to 17m/s. find the change in momentum of the car?
lisabon 2012 [21]

Answer:

4800

Explanation:

The change in velocity of the car is 17-13=4m/s. Since the change in momentum is the mass multiplied by the change in velocity, the answer is 4*1200=4800. Hope this helps!

6 0
4 years ago
A baseball m=.34kg is spun vertically on a massless string of length l=.52m. the string can only support a tension of tmax=9.9n
larisa86 [58]
<span>4.5 m/s This is an exercise in centripetal force. The formula is F = mv^2/r where m = mass v = velocity r = radius Now to add a little extra twist to the fun, we're swinging in a vertical plane so gravity comes into effect. At the bottom of the swing, the force experienced is the F above plus the acceleration due to gravity, and at the top of the swing, the force experienced is the F above minus the acceleration due to gravity. I will assume you're capable of changing the velocity of the ball quickly so you don't break the string at the bottom of the loop. Let's determine the force we get from gravity. 0.34 kg * 9.8 m/s^2 = 3.332 kg m/s^2 = 3.332 N Since we're getting some help from gravity, the force that will break the string is 9.9 N + 3.332 N = 13.232 N Plug known values into formula. F = mv^2/r 13.232 kg m/s^2 = 0.34 kg V^2 / 0.52 m 6.88064 kg m^2/s^2 = 0.34 kg V^2 20.23717647 m^2/s^2 = V^2 4.498574938 m/s = V Rounding to 2 significant figures gives 4.5 m/s The actual obtainable velocity is likely to be much lower. You may handle 13.232 N at the top of the swing where gravity is helping to keep you from breaking the string, but at the bottom of the swing, you can only handle 6.568 N where gravity is working against you, making the string easier to break.</span>
7 0
3 years ago
Read 2 more answers
Work-Energy Theorem: A 4.0 kg object is moving with speed 2.0 m/s. A 1.0 kg object is moving with speed 4.0 m/s. Both objects en
allsm [11]

The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:

FΔx = 0.5mv²

F = force, Δx = distance traveled, m = mass, v = speed

Isolate Δx:

Δx = 0.5mv²/F

Calculate Δx for each object.

Object 1: m = 4.0kg, v = 2.0m/s

Δx = 0.5(4.0)(2.0)²/F = 8/F

Object 2: m = 1.0kg, v = 4.0m/s

Δx = 0.5(1.0)(4.0)²/F = 8/F

The two objects travel the same distance before stopping.

4 0
3 years ago
A child in danger of drowning in a river is being carried downstream by a current that flows due south uniformly with a speed of
tia_tia [17]

Let the rescue boat starts at an angle theta with the North

now its velocity towards East is given as

v_x = 24sin\theta

v_y = -24cos\theta + 3

now in some time "t" it will catch the boy

so we will have

t = \frac{0.5}{24sin\theta}

also we have

t = \frac{2}{-24cos\theta + 3}

now we have

\frac{2}{-24cos\theta + 3} = \frac{0.5}{24sin\theta}

4*24sin\theta = - 24cos\theta + 3

96 sin\theta + 24cos\theta = 3

by solving above we got

\theta = 164 degree

3 0
3 years ago
Pls help I’m in a middle of a test and I can’t find the answer
EastWind [94]

Answer:

I believe the answer is B.

5 0
1 year ago
Read 2 more answers
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