Answer: (0,3) & (0,-1)
Step-by-step explanation:
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
#SPJ1
Answer:
1/3
Step-by-step explanation:
1/2 James' fraction of Michael
2/3 Trina's fraction of James
1/2 x 2/3 = 1/3
I have no clue what the answer would be, I’ve worked on it for 25 minutes, I will get back to you if I figure it out :,)
Answer:
801/1000
Step-by-step explanation: