Given:
Polynomial
To find:
The values of x.
Solution:
Quadratic equation formula:
Here .
Substitute the values in the formula, we get
Option E and option F are the roots of the polynomial.
The values of x are .
What is the radius of the circle with equation x2 + y2 – 8x + 12y – 5 = 0?
1 answer:
You might be interested in
Option C:
x = 90°
Solution:
Given equation:
<u>To find the degree:</u>
Subtract 1 + cos²x from both sides.
Using the trigonometric identity:
Let sin x = u
Factor the quadratic equation.
u + 2 = 0, u – 1 = 0
u = –2, u = 1
That is sin x = –2, sin x = 1
sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.
sin x = 1
The value of sin is 1 for 90°.
x = 90°.
Option C is the correct answer.
