Answer: 0.050
Explanation:
Mean = 18
USL = 18.6
LSL = 17.4
SD = 1.25
Cpk = Min{(mean - LSL / 3*sd), (USL - mean / 3*sd)}
= Min{ ( 18 - 17.4/ 3 * 1.25), (18.6 - 18 / 3 * 1.25)}
= Min { 0.05 0.05)
Cpk = 0.050
Answer: Budgeted Raw Material to be consumed in July.
Quantity Price per pound Total
10,200 $6 $61,200
Explanation:
As for the information provided, the material at month end in hand shall be:
20% of upcoming month's sale.
If in June at month end, the inventory in hand = 2,040 pounds of raw material.
Then, this represents 20% of total requirement of July.
Therefore, total requirement in July = 
This basically means:
Total inventory required =
Quantity Price per pound Total
10,200 $6 $61,200
The meta-analysis is the best represent as a statistical action, that which involves quantitatively pooling the data from a group of independent studies that have studied the same or similar clinical problems, by using the same or similar research methods.
Answer:
Present value (PV) = $1,000
Interest rate (r) =8% = 0.08
Number of years (n) = 18 months = 1.5 years
No of compounding periods in a year = 4
Future value (FV) = ?
FV = PV(1 + r/m)nm
FV = $1,000(1 + 0.08/4)1.5x4
FV = $1,000(1 + 0.02)6
FV = $1,000 x 1.1262
FV = $1,126
Explanation:
The amount to be received in 18 months is $1,126. This is obtained by compounding the present value at 8% compounded quarterly for 18 months. The formula to be applied is the formula for future value of a lump sum(single investment).
Answer:
The marginal rate of technical substitution will remain constant.
Explanation:
The marginal rate of technical substitution is the rate at which an input is substituted for others. For instance, it is the rate at which the amount of labor should be decreased to increase the amount of capital.
It represents the slope of an isoquant. When the inputs are perfectly substitutable, the isoquant is a straight line. In this situation, the marginal rate of technical substitution remains the same at all the points of the isoquants. The MRTS remains constant, though further information is needed to find out if it is high or low.
