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grin007 [14]
3 years ago
10

Speed of an electron to orbit radius wire linear charge density is _________

Chemistry
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

A long uniformly charged wire has charge density λ=0.16μλ=0.16μC/m. 

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The internet is a local communication network that allows only certain computers to connect and exchange information True or fal
choli [55]
False, the internet branches throughout many countries connecting you to the rest of the world from home. Hope it helped!
6 0
3 years ago
The isomerization of methylisonitrile to acetonitrileCH3NC(g)→CH3CN(g)is first order in CH3NC . The rate constant for the reacti
lisabon 2012 [21]

Answer:

Option E, Half life = 2.96\times 10^3\ s

Explanation:

For a first order reaction, rate constant and half-life is related as:

            t_{1/2}=\frac{0.693}{k}

Where,

t_{1/2} = Half life

k = Rate constant

Rate constant given = 2.34\times 10^{-4}\ s^{-1}

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{2.34 \times 10^{-4}}=2.96\times 10^3\ s

So, the correct option is option E.

4 0
3 years ago
If the stack of bricks on the right has a mass of 240 kg, approximately what is the mass of the stack of bricks on the left?
solong [7]

Answer:

720

Explanation: study island

4 0
3 years ago
Read 2 more answers
When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

6 0
3 years ago
I beg you to help me in this and im gonna mark u as brainliest but fassttt
Anni [7]

Explanation:

F = nucleus

G = cell membrane

H = cytoplasm

J = cell wall

k = vacoule

L = plastids

mark me brainiest?

6 0
3 years ago
Read 2 more answers
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