6. Which change to a population would cause

Type the correct answer in the box. Express your answer to two significant figures. An industrial vat contains 650 grams of soli

nikklg [1K]

88.98 %

The Balance Chemical Equation is as follow,

2 HCl + Pb(NO₃)₂ → 2 HNO₃ + PbCl₂

According to equation,

331.2 g (1 mole) Pb(NO₃)₂ produces = 278.1 g (1 mole) PbCl₂

So,

870 g of Pb(NO₃)₂ will produce = X g of PbCl₂

Solving for X,

X = (870 g × 278.1 g) ÷ 331.2 g

X = 730.5 g of PbCl₂

Therefore,

Theoretical Yield = 730.5 g

Also as given,

Actual Yield = 650 g

So using following formula for percentage yield,

%age Yield = (Actual Yield / Theoretical Yield) × 100

Putting values,

%age Yield = (650 g / 730.5 g) × 100

%age Yield = 88.98 %

Brianliest please and thank you.

6 0

3 years ago

What might cause your stomach pH to become more acidic than normal

Jet001 [13]

It might be that its difficult to digest food.

6 0

3 years ago

Which characteristic might identify a substance as an Arrhenius base?

Scorpion4ik [409]

Answer: a

Explanation: because an Arrhenius acid is a compound that increases the H + ion concentration in aqueous solution. An Arrhenius base is a compound that increases the OH − ion concentration in aqueous solution.

5 0

3 years ago

Read 2 more answers

When heating liquid materials in laboratory glassware, a student should always

Lelechka [254]

Answer:

be careful to not hurt yourself

5 0

3 years ago

Read 2 more answers

A solution is prepared by mixing 50.0 mL toluene (C6H5CH3 d=0.867 g/mL) with 125 mL Benzene (C6H6 d=0.874 g/mL). Assuming that t

Tatiana [17]

Answer:

mass % = 28.4%

mole fraction = 0.252

molality = 3.08 molal

molarity = 2.69 M

Explanation:

Step 1: Data given

Volume of toluene = 50.0 mL = 0.05 L

Density toluene = 0.867 g/mL

Molar mass toluene = 92.14 g/mol

Volume of benzene = 125 mL = 0.125 L

Density benzene = 0.874 g/mL

Molar mass benzene = 78.11 g/mol

Step 2: Calculate masses

Mass = density * volume

Mass toluene = 50.0 mL * 0.867 g/mL = 43.35 g

Mass benzene = 125 mL * 0.874 g/mL = 109.25 g

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles toluene = 43.35 grams /92.14 g/mol = 0.470 5 moles

Moles benzene = 109.25 grams / 78.11 g/mol = 1.399 moles

Step 4: Calculate molarity of toluene

Molarity = moles / volume

Molarity toluene = 0.4705 moles / 0.175 L = 2.69 M

Step 5: Calculate mass % of toluene

Mass % = (43.35 grams / (43.35 + 109.25) )*100 % = 28.4 %

Step 6: Calculate mole fraction of toluene

Mole fraction toluene = Moles toluene / total number of moles

Mole fraction toluene = 0.4705 / (0.4705 + 1.399) = 0.252

Step 7: Molality of toluene

Molality = number of moles / mass

Molality of toluene = 0.4705 moles / (0.04335 + 0.10925)

Molality of toluene = 3.08 molal

4 0

3 years ago