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Oliga [24]
3 years ago
14

What is the wavelength of radiation that has a frequency of 5.9×1011 s−1 ?

Chemistry
1 answer:
Igoryamba3 years ago
3 0

Answer:

frequency = velocity of light /wavelength

wavelength = velocity / frequency

=3 x10^8 / 5.9 x 10^11

=0.508 x 10^-3.

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Chlorine<span> is a </span>gas at room temperature.<span>The melting/boiling point of a substance determines what state of matter it takes at a certain temperature.</span> 
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Which isolated gaseous atom has a total of six electron occupying spherical shaped orbitals
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Carbon

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Can acidic oxide react with acids?<br> If not, why?
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249 g of potassium iodide, KI, is mixed with 496.5 g of lead(II) nitrate, Pb(NO3)2.
sveticcg [70]

<u>Answer: </u>The number of moles of excess reagent left is 0.750 moles

<u>Explanation:</u>

The number of moles is calculated by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For KI:</u>

Given mass of KI = 249 g

Molar mass of KI = 166 g/mol

Putting values in equation 1, we get:

\text{Moles of KI}=\frac{249g}{166g/mol}=1.5mol

  • <u>For </u>Pb(NO_3)_2<u>:</u>

Given mass of Pb(NO_3)_2 = 496.5 g

Molar mass of Pb(NO_3)_2 = 331 g/mol

Putting values in equation 1, we get:

\text{Moles of }Pb(NO_3)_2=\frac{496.5g}{331g/mol}=1.5mol

The given chemical equation follows:

2KI+Pb(NO_3)_2\rightarrow 2KNO_3+PbI_2

By stoichiometry of the reaction:

If 2 moles of KI reacts with 1 mole of lead(II) nitrate

So, 1.5 moles of KI will react with = \frac{1}{2}\times 1.5=0.75mol of lead(II) nitrate

As the given amount of lead(II) nitrate is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, KI is considered a limiting reagent because it limits the formation of the product.

Moles of excess reactant (Pb(NO_3)_2) left = [1.5 - 0.75] = 0.750 moles

Hence, the number of moles of excess reagent left is 0.750 moles

8 0
3 years ago
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