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4 years ago

What is voltage?

Physics

2 answers:

Andrews [41]4 years ago

5 0

<span>C. It is the difference in electrical potential energy between two places in an electric field.</span>

marin [14]4 years ago

3 0

Answer:

C. It is the difference in electrical potential energy between two places in an electric field.

Explanation:

The voltage, also known as voltage or potential difference is a physical quantity that drives electrons along a conductor in a closed electrical circuit, causing the flow of an electric current.

The potential difference is also defined as the work per unit of charge exerted by the electric field, on a charged particle, to move it from one place to another. It can be measured with a voltmeter.

In the International System of Units, the potential difference is measured in Volts (V), as is the Potential.

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A unit of time sometimes used in microscopic physics is the "shake". One shake equals 10−8 s.

Lady_Fox [76]

Answer:

(a) There are 3.17 times more shakes in a second than seconds in a year.

(b) Humans have existed for 9067.72 universe seconds.

Explanation:

(a) First we calcule how many seconds are in a year. One year have 365 days, one day has 24 hours, one hour has 60 minutes and one minute has 60 seconds, so:

$60s*60*24*365=3.1536*10^7s$

Now, we calculate how many shakes are in a second:

$1s*\frac{1shake}{10^{-8}s}=10^8shakes$

Finally, we calculate how many more shakes in a second are there than seconds in a year:

$\frac{10^8s}{3.1536*10^7s}=3.17$

(b) Using a simple rule of three we can calculate how many "universe seconds" have humans existed, recall that 1 day has 86400 seconds:

1010 years--------->86400s

106 years----------> x seconds

$x=\frac{106y*86400s}{1010y}=9067.72s$

3 0

3 years ago

What is the thermal energy of an object

Dimas [21]

The thermal energy of an object is defined as the total translational kinetic energy of the particles that make it up.

The answer is B.

8 0

4 years ago

Read 2 more answers

7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is

Gekata [30.6K]

Answer:

Approximately $1\; \rm kg$ . (Assumption: $g = 9.8\; \rm m \cdot s^{-2}$ .)

Explanation:

Let the mass of this ball be $x\; \rm kg$ .

Initial gravitational potential energy of this ball: $m \cdot g \cdot h \approx (39.2\, x) \; \rm J$ .

Just before the ball hits the ground, all $(39.2\, x)\; \rm J$ of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:

$\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}$ .

Therefore, right before hitting the ground, the velocity of the ball would be:

$\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}$ .

The momentum $p$ of an object of mass $m$ and velocity $v$ would be $p = m \cdot v$ . Rewrite this equation to find an expression for mass $m\!$ given velocity $v\!$ and momentum $p\!$ :

$\displaystyle m = \frac{p}{v}$ .

Right before collision, the momentum of this ball is $p = 8.85\; \rm kg \cdot m \cdot s^{-1}$ while its velocity is $v \approx 8.85\; \rm m \cdot s^{-1}$ . Therefore, the mass of this ball would be:

$\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}$ .