<span>the smallest structural and functional unit of an organism, typically microscopic and consisting of cytoplasm and a nucleus enclosed in a membrane. Microscopic organisms typically consist of a single cell, which is either eukaryotic or prokaryotic.</span>
0.050 M Urea, 0.10 M glucose, 0.20 M sucrose and pure water.
<u>Explanation:</u>
Vapor pressure is the measure of pressure existing above the surface of the solution. Depending upon the vapor pressure of solutions, the boiling points will differ. In other words, decrease in vapor pressure leads to increase in the boiling point.
Since, the number of molecules present above the surface of the solution leads to easy evaporation of those molecules. But if the number of molecules on the surface or vapor pressure on the surface will be less, the boiling point will increase.
Thus, 0.050 M urea has the highest vapor pressure indicating that it can be easily evaporated, then 0.10 M of glucose has the vapor pressure followed by 0.20 M sucrose. Finally, the vapor pressure of water is the lowest and it will have the boiling point of 100 degree celsius.
Answer:
(a). The thickness of the glass is 868 nm.
(b). The wavelength is 3472 nm.
Explanation:
Given that,
Refractive index = 1.20
Wavelength = 496 nm
Next wavelength = 386 nm
We need to calculate the thickness of the glass
Using formula for constructive interference
Put the value into the formula
In first case,
.....(I)
In second case,
.....(II)
From equation (I) and (II)
Put the value of m in equation (I)
The thickness of the glass is 868 nm.
(b). We need to calculate the wavelength
Using formula of constructive interference
Put the value into the formula
Hence, (a). The thickness of the glass is 868 nm.
(b). The wavelength is 3472 nm.
Answer:
Answer is 20
Explanation:
As we know
\Large\boxed{ \tt{}F =ma}
F=ma
Here Given
★ F = 100
★ m = 25 kg
Putting in the equation
\leadsto\tt{100=25\times\:a}⇝100=25×a
On solving
\sf{\dashrightarrow\:a = 4 \:ms^{-2}}⇢a=4ms
−2
Now the body initially is stationary therefore initial velocity (u) must be zero
u = 0
Applying Newton 1st Law of Motion :
\sf\Large\boxed{ \tt{}v =u + at}
v=u+at
Substituting the values to find final velocity at t= 5 sec
\leadsto \tt{v = 0 + 4 \times \:5}⇝v=0+4×5
\tt{ \pink{\dashrightarrow\:v = 20 \:m/s}}⇢v=20m/s
☞ Hence, the final velocity is 20 m/s