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sashaice [31]
2 years ago
12

You throw a rock up into the air as hard as you can. It stays in the air a total of 6.0 s. What

Physics
1 answer:
vaieri [72.5K]2 years ago
6 0

Answer:

<h2>5.9 x 10</h2>

Explanation:

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A 357 kg box is pulled 8.00 m up a 30° frictionless, inclined plane by an external force of 4925 N that acts parallel to the pla
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3 years ago
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2 years ago
Why would Sodium(Na) and Chlorine (CI) want to form a lonic Bond?
miskamm [114]

Answer: to achieve a stable octet of electrons in their outer shell

Explanation:

- Sodium (Na) has an atomic number of 11, and an electronic configuration of 1s2, 2s2 2p6, 3s1.

- Chlorine (CI) Sodium (Na) has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5.

Hence, sodium donates its single valence electron to chlorine, thereby achieving a stable octet structure of 1s2, 2s2 2p6 while chlorine accept the single electron also forming a stable octet structure of 1s2, 2s2 2p6, 3s2 3p6. Therefore, the reaction yields NaCl, an ionic compound with ionic (electrovalent) bond.

Na + Cl --> NaCl

Thus, Sodium(Na) and Chlorine (CI) want to form a lonic Bond because both acheive a completely filled outermost shell (octet structure)

3 0
3 years ago
Question 1: Bicycle pump
belka [17]

Answer: The pressure  of the air when compressed is 5.0\times 10^5Pa

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_1=P_2V_2  

where,

P_1 = initial pressure of gas  = 1.0\times 10^5Pa

P_2 = final pressure of gas  =?

V_1 = initial volume of gas  = V

V_2 = final volume of gas  = \frac{V}{5}

1.0\times 10^5\times V=P_2\times \frac{V}{5}  

P_2=5.0\times 10^5Pa

Therefore, the pressure  of the air when compressed is 5.0\times 10^5Pa

4 0
3 years ago
Physics is really confusing...is there anyone that can show it to me?
coldgirl [10]

Answer:

1.0×10³ N

Explanation:

μs is the static coefficient of friction.  That's the friction that acts on a stationary (non-moving) object when being pushed or pulled.

μk is the kinetic coefficient of friction.  That's the friction that acts on a moving object.

To budge the pig (while it's still stationary), we need to overcome the static friction.

F = N μs

For a non-moving object on level ground, the normal force N equals the weight.

F = mg μs

Given m = 130 kg and μs = 0.80:

F = (130 kg) (9.8 m/s²) (0.80)

F = 1019.2 N

Rounded to two significant figures, the force needed to budge the pig is 1.0×10³ N.

3 0
3 years ago
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