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Westkost [7]
3 years ago
13

The Moon orbits Earth in an average of p = 27.3 days at an average distance of a =384,000 kilometers. Using Newton’s version of

Kepler’s third law determine the mass of Earth. You may neglect the mass of the Moon in comparison to the mass of Earth.
Physics
1 answer:
Korvikt [17]3 years ago
7 0

Answer:

The mass of the earth, M=6.023\times 10^{24}\ kg

Explanation:

It is given that,

Time taken by the moon to orbit the earth, T=27.3\ days=2358720\ m

Distance between moon and the earth,r=384000\ km=384\times 10^6\ m

We need to find the mass of the Earth using Kepler's third law of motion as :

T^2=\dfrac{4\pi^2}{GM}r^3

M=\dfrac{4\pi^2r^3}{T^2G}

M=\dfrac{4\pi^2\times (384\times 10^6)^3}{(2358720)^2\times 6.67\times 10^{-11}}

M=6.023\times 10^{24}\ kg

So, the mass of the earth is 6.023\times 10^{24}\ kg. Hence, this is the required solution.

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Correct choices are marked in bold:

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move by particles bumping into each other  --> FALSE, electromagnetic waves are oscillations of electric and magnetic fields, so no particles are involved

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8 0
3 years ago
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It takes 9 sec for a 10 newton force to move an object 4 meters to the right. What is direction & magnitude of the force
lana66690 [7]

Answer:

the question is wrong

Explanation:

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  3. ((10/Mm/s *9s-)
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3 years ago
You go to the hardware store to buy a new 50 ft garden hose. You find you can choose between hoses of ½ inch and 5/8 inch inner
omeli [17]

To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,

Q = V*A

Where,

A= Cross-sectional Area

V = Velocity

The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,

Q_1 = Q_2

V_1A_1=V_2A_2

Our values are given as,

A_1=\frac{1}{2}^2*\pi=0.785 in^2

A_2=\frac{5}{8}^2*\pi=1.227 in^2

Re-arrange the equation to find the first ratio of rates we have:

\frac{V_1}{V_2}=\frac{A_2}{A_1}

\frac{V_1}{V_2}=\frac{1.227}{0.785}

\frac{V_1}{V_2}=1.56

The second ratio of rates is

\frac{V2}{V1}=\frac{A_1}{A2}

\frac{V2}{V1}=\frac{0.785}{1.227}

\frac{V2}{V1}=0.640

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3 years ago
Which of the following is the most important reason why simple harmonic motion will not continue forever in most real-world situ
d1i1m1o1n [39]
<span>A.frictional effects dissipate energy.</span>
4 0
3 years ago
Time (s)
olya-2409 [2.1K]

The moon orbiting the Earth

Explanation:

The motion of the moon orbiting the earth is a circular motion. Circular motion is simply the motion of an object in circle at constant speed.

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Learn more:

Circular motion brainly.com/question/2562955

#learnwithBrainly

7 0
3 years ago
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