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ale4655 [162]
3 years ago
15

What does it mean if an experiment is replicable? Why is it important that experiments be replicable? (Site 1)

Physics
1 answer:
Arisa [49]3 years ago
5 0

If an experiment is replicsble it means that anybody can repeat the experiment and get the same results. It is important that experiments be replicable because if someone else can't repeat what you did, you might have made a mistake. Peer review is what scientists use.

hope this helps

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How do I find the magnitude of the net force acting on the box
prohojiy [21]

Answer:

20 N

Explanation:

<em>Newton's second Law of motion</em> law states that If there is a external force acting on an object. Then the rate of change of momentum of  that object is directly proportional to the force acting on its.

  • the net force acting upon the object  <em>(F)</em>
  • the mass of the object. <em>(m)</em>
  • <em>V </em>Final velocity of the object
  • U initial velocity of the object
  • mV -Final momentum of the object
  • mU - Initial momentum of the object

Due to momentum change of that object, momentum change. We can write the equation bellow this,

F = (mV-mU)/t

When m is constant we can write the above expression like this,

F = m (V-U)/t

There for

(V-U)/t  =  a ( Rate of change of velocity can be denoted as acceleration )

F = m× a

we can state this in mathematically,

a = F/m

in another representation

F = m*a

Net Force = mass*acceleration

                 = 10 * 2

                 = 20 N

object is subjected to a negative acceleration due to the friction.

4 0
3 years ago
What is kinematics ???<br>need a legendary answer -,-" <br>xD ​
Alenkasestr [34]

Explanation:

the features or properties of motion in an object

7 0
2 years ago
Read 2 more answers
You are given two vectors vector A = 4.9 at 31o vector B = 6 at 156o Angles are measured counterclockwise from the x-axis. What
Ket [755]

Answer:

   C_{y} = 4.96  and     θ' = 104,5º

Explanation:

To add several vectors we can decompose each one of them, perform the sum on each axis, to find the components of the resultant and then find the module and direction.

Let's start by decomposing the two vectors.

Vector A

             sin θ = A_{y} / A

             cos θ = Aₓ / A

             A_{y} = A sin  θ

             Ax = A cos θ

             A_{y} = 4.9 sin 31 = 2.52

             Ax = 4.9 cos 31 = 4.20

Vector B

           B_{y} = B sin θ

           Bx = B cos θ

           B_{y} = 6 sin 156 = 2.44

           Bx = 6 cos 156 = -5.48

The components of the resulting vector are

X axis

         Cx = Ax + B x

         Cx = 4.20 -5.48

         Cx = -1.28

Axis y

         C_{y} = Ay + By

         C_{y} = 2.52 + 2.44  

         C_{y} = 4.96

Let's use the Pythagorean theorem to find modulo

         C = √ (Cₙ²x2 + Cy2)

         C = Ra (1.28 2 + 4.96 2)

         C = 5.12

We use trigonemetry to find the angle

         tan θ = C_{y} / Cₓ

          θ’ = tan⁻¹ (4.96 / (1.28))

           θ’ = 75.5

como el valor de Cy es positivo y Cx es negativo el angulo este en el segundo cuadrante, por lo cual el angulo medido respecto de eje x positivo es

       θ’ = 180 – tes

        θ‘= 180 – 75,5

        θ' = 104,5º

7 0
2 years ago
A length of wire is cut into five equal pieces. if each piece has a resistance of 0.45 ω, what was the resistance of the origina
azamat
Calculation, add them. 0.85 x 5 = 4.25 Ω
5 0
3 years ago
When it is at rotating at full speed, a disk drive in a certain old computer game system revolves once every 0.050 seconds. Star
Gemiola [76]

Answer:

α = 200*π rad/sec²

Explanation:

  • If the disk drive revolves once every 0.05 sec, this means that the angular velocity can be expressed as follows:

        \omega = \frac{2*\pi}{0.05s} = 40*\pi rad/sec

  • (just applying the definition of angular velocity)
  • Now, it the disk started from rest, and took two revolutions to reach to full speed, assuming that the angular acceleration is constant, we can find the angular acceleration applying this kinematic equation:

        \omega_{f} ^{2} -\omega_{0} ^{2} = 2*\alpha * \Delta\theta

  • where Δθ, is the angle rotated while it went from rest to full speed, i.e., 2 revolutions, or 2*π rads.
  • Replacing by the value that we found for ωf (as ω₀ = 0), we  can solve for α :

       \alpha =\frac{\omega_{f}^{2} }{2*\Delta\theta} = \frac{(40*\pi)^{2} }{2*2*2*\pi } =\\ \\ \alpha = 200*\pi rad/sec2

3 0
3 years ago
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