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ale4655 [162]
4 years ago
15

What does it mean if an experiment is replicable? Why is it important that experiments be replicable? (Site 1)

Physics
1 answer:
Arisa [49]4 years ago
5 0

If an experiment is replicsble it means that anybody can repeat the experiment and get the same results. It is important that experiments be replicable because if someone else can't repeat what you did, you might have made a mistake. Peer review is what scientists use.

hope this helps

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A 600kg car is at rest , and then accelerates to 5n/s what is the original kinetic energy?
lubasha [3.4K]
M = 600 kg
u = 0 (as the car was at rest initially)
v = 5 m/s
Initial kinetic energy = ½mu²
= ½×600×0
= 0
Final kinetic energy = ½mv²
= ½×600×25
= 7500 J
7 0
4 years ago
A supply plane needs to drop a package of food to scientists working on a glacier in greenland. the plane flies 100 m above the
pishuonlain [190]

The package should be dropped <u>678 m</u> short of the target.

A package dropped from a plane which is moving at a speed v, has a horizontal velocity equal to the horizontal velocity of the plane. It has a parabolic trajectory, traversing a horizontal range x while it falls through a vertical height y.

The package has no initial vertical velocity, and it falls through a height y under the action of the acceleration due to gravity g.

Use the equation,

y=\frac{1}{2} gt^2

Write an expression for t, the time taken for the package to fall through y.

t^2=\frac{2y}{g}

Substitute 100 m for y and 9.81m/s² for g.

t^2=\frac{2y}{g}\\ =\frac{2(100m)}{9.81m/s^2} \\ =20.39s^2\\ t=4.52s

In the time t  the package travels a horizontal distance x. The horizontal velocity of the package remains constant, since no force acts along the horizontal direction.

Therefore, the horizontal distance traveled by the package is given by,

x=vt\\ =(150m/s)(4.52s)\\ =678m

If the package is released <u>678m</u> before the target, the package would reach the scientists working in Greenland.

6 0
4 years ago
Two gliders on an air track collide in a perfectly elastic collision. Glider A has a mass of 1.1 kg and is initially travelling
Eva8 [605]

m1= mass 1 = 1.1 kg

Vi1 = initial velocity 1 = 2.7 m/s

m2= 2.4 kg

V2i = -1.9 m/s

We assume east as positive and west as negative.

Apply the formulas:

Vf1 = ?

vf1=(\frac{m1-m2}{m1+m2})Vi1+(\frac{2m2}{m1+m2})Vi2

Replacing:

Vf1=\frac{(1.1-2.4)}{(1.1+2.4)}2.7+\frac{(2\times2.4)}{(1.1+2.4)}-1.9Vf1=(\frac{-1.3}{3.5})2.7+(\frac{4.8}{3.5})-1.9Vf1=-1-2.6=-3.6\text{ m/s}

Answer: 3.6 m/s west

6 0
1 year ago
Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.
Andrei [34K]

Answer: A

Explanation: We know that f=p*n

f=50*300=15000 Hz = 15kHz.

Have a great day! <3

3 0
2 years ago
Whta is the mechanical advantage when the effort force is 20 and the resistance force is 5
pogonyaev
The mechanical advantage would be 4. 20/5=4
7 0
3 years ago
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