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Yuri [45]
3 years ago
14

A stone is thrown horizontally at 15 m/s from the top of a cliff 40 meters high. How far from the base does the stone hit the gr

ound?
PLS HELP
Physics
1 answer:
Reil [10]3 years ago
5 0

Answer:

She stone hit ground 42.86 m far from base of cliff.

Explanation:

  Initial height from ground = 40 meter.

We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 m/s^2, we need to calculate time when s = 40 meter.

Substituting

40=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.86 seconds

So it will take 2.86 seconds to reach ground.

So, stone travels horizontally at 15 m/s for 2.86 seconds.

Distance travelled = 15 x 2.86 = 42.86 m

So, the stone hit ground 42.86 m far from base of cliff.


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A diverging lens (f1 = -12.0cm) is located 50.0 cm to the left of a converging lens (f2 = 34.0 cm). A 2.0 cm-tall object stands
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Answer:

The final image relative to the converging lens is 34 cm.

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Focal length of diverging lens = -12.0 cm

Focal length of converging lens = 34.0 cm

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Distance of object = 12 cm

Because object at focal point

We need to calculate the image distance of diverging lens

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{-12}-\dfrac{1}{-12}

v=\infty

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We need to calculate the image distance of converging lens

Now, object distance is ∞

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{34}-\dfrac{1}{\infty}

v=34

The image distance is 34 cm right to the converging lens.

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The electric field between the plates of the cathode ray tube of an older television set can be as high as 2.5x104 N/C. Determin
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Answer:

(a) F = -4.01 * 10^{-15} N

(b) a = 4.40 * 10^{15} m/s^2

Explanation:

Parameter given:

Electric field, E = 2.5 * 10^4 N/C

(a) Electric force is given (in terms of electric field) as a product of electric charge and electric field.

Mathematically:

F = qE

Electric charge, q, of an electron = - 1.602 * 10^{-19} C

F = -1.602 * 10^{-19} * 2.5 * 10^4\\\\\\F = -4.01 * 10^{-15} N

(b) This electrostatic force causes the electron to accelerate with an equivalent force:

F = -ma

where m = mass of an electron

a = acceleration of electron

(Note: the force is negative cos the direction of the force is opposite the direction of the electron)

Therefore:

-ma =  -4.01 * 10^{-15} N\\\\\\a = \frac{-4.01 * 10^{-15}}{-m}

Mass, m, of an electron = 9.11 * 10^{-31} kg

=> a = \frac{-4.01 * 10^{-15}}{-9.11 * 10^{-31}}\\\\\\a = 4.40 * 10^{15} m/s^2

The acceleration of the electron is 4.40 * 10^{15} m/s^2

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